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3 years ago

Quadrilateral BCDE is a rhombus. What is DE? D с 9z E 2+72 B

Mathematics

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

DE = 81

Step-by-step explanation:

The sides of a rhombus are congruent , thus

9z = z + 72 ( subtract z from both sides )

8z = 72 ( divide both sides by 8 )

z = 9

Then

BC = 9z = 9 × 9 = 81

Since the sides are congruent, then DE = 81

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3 years ago

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Nonamiya [84]

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Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
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