All categories

2 years ago

Find the multiplicative inverse of: a)3^-4 b)7^-3 c)10^-50 help me ASAP

Mathematics

1 answer:

castortr0y [4]2 years ago

6 0

Answer:

como estas buena mada mala :) the answer is B

Step-by-step explanation:

i hope i helped!! :D :)))

You might be interested in

Write as a mathematical equation. The product of 5 and x is 25.

pickupchik [31]

answer:

5x=25

Divide 5 from both sides

5x/5=25/5

x=5

4 0

3 years ago

Which degree of rotation is equivalent to a 270 degree clockwise rotation?

Dominik [7]

A 90 degree counter clockwise rotation

4 0

2 years ago

598839582985928390-583853p98928

eduard

What is this question supposed to be?

7 0

2 years ago

Read 2 more answers

If p represents the original price, which of the following expressions could be used to calculate the sale price of a shirt that

dezoksy [38]

Answer:

C & D

Step-by-step explanation:

You can do these two ways. You can multiply the cost of the the shirt by 15% (.15 as a decimal.) and then subtract that answer from the original price of the shirt to get the sales price of the shirt.

You can also multiply the price of the shirt by 85% (.85 as a decimal) and that will give you the sales price without having to subtract. 15% + 85% = 100%, so 85% represents the sales price of the shirt.

Anyway, since you multiply, you can eliminate choice A & B.

Since the direction in the question says to select all that apply, I would check both C & D.

C is the equation of the first way I talked about- Price - 15% * price

C p - 0.15p

D is the equation of the second way I talked about. Price times 85%

D 0.85p

7 0

2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago