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Rom4ik [11]
2 years ago
12

The figure below represents a reaction.What type of reaction is shown?

Chemistry
1 answer:
o-na [289]2 years ago
7 0
Are you sure it isn’t SO3+H2O = H2SO4 because that would be combination (synthesis) A+ B=AB

Or SO3 + H2SO4 = H2S2O7
Because that would also be synthesis
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A 1 mL pipette delivers a measured volume of .98 mL (calculate the percentage error)
Natalija [7]

Answer:

2%

Explanation:

.98 is 98% of one and therefore they are missing 2%

4 0
3 years ago
Read 2 more answers
How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
2 years ago
Read 2 more answers
Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.
11Alexandr11 [23.1K]

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)


5 0
3 years ago
Read 2 more answers
HELP ME PLEASE !!! I.D.K WHAT TO DO :((( Will mark brainliest please !!
Svetradugi [14.3K]
I’m sorry but where’s the worksheet lol......
7 0
3 years ago
Read 2 more answers
If you put to the electrons and hydrogen making it a negative charge does that make it stable or unstable
Romashka-Z-Leto [24]

I'm pretty sure it would make it unstable, hydrogen only has one proton thus having the ability to stabilize one electron, adding another electron would most likely make the atom reactive to any positively charged atom to loose this extra electron.

8 0
2 years ago
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