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mixer [17]
3 years ago
6

Write 0.034 in scientific notation.

Chemistry
2 answers:
Doss [256]3 years ago
7 0

Answer:

0.034 = 34×10^-3

Explanation:

This is because the special point is notated until it goes in front of the first counting number

NARA [144]3 years ago
4 0

Answer:

oink

Explanation:

mooo

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NEED HELP ASAP!! MY BRAINLEST IS GIVING 50-100 POINTS!! NUMBER THEM 1-10!!
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Answer:

1. A      2. C      3. A         4. B          5. C       6. A       7. B         8. A      9. C       10. B

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When 1.550 g of liquid hexane (C6H14) undergoes combustion in a bomb calorimeter, the temperature rises from 25.87∘C to 38.13∘C.
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Explanation:

1). The given data is as follows.

       T_{i} = 25.87^{o}C,      T_{f} = 38.13^{o}C

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Hence, calculate the change in enthalpy of the reaction as follows.

      \Delta E_{rxn} = -C \times \Delta T

                     = -5.73 \times (38.13 - 25.87)^{o}C

                     = -70.25 KJ

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                                    = \frac{1.55}{(6 \times 12 + 14 \times 1)}

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Therefore, enthalpy of reaction in kJ/mol hexane is as follows.

            \Delta E_{rxn} = \frac{-70.25 KJ}{0.018 mol}

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Thus, we can conclude that \Delta E_{rxn} for the reaction in kJ/mol hexane is -3.90 \times 10^{3} kJ/mol .

2).  As we know that,

     Number of moles = \frac{mass}{\text{molar mass}}

                                  = \frac{1.55}{(7 \times 12 + 8 \times 1)}

                                   = 0.017 mol

       \Delta E_{rxn} = \E_{rxn} per mol \times \text{number of moles}

                      = -3.91 \times 10^{3} \times 0.017

                      = -65.875 kJ

As,    \Delta E_{rxn} = C \times \Delta T


                    -65.875 kJ = -C \times (37.57 - 23.12)^{o}C

                           C = 4.56 kJ/^{o}C

Hence, heat capacity of the bomb calorimeter is 4.56 kJ/^{o}C.

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