A _____ ionic compound is a polyatomic ionic compound composed of three or more different elements.

What is the chemical formula for the ternary compound composed of co3+ and so42- ions? coso4 co3(so4)2 co2so4 co2(so4)3 none of

Andreas93 [3]

If you are provided with Cation and an Anion with different oxidation states, then there ratio in the formula unit is adjusted as such that the oxidation number of one ion is set the coefficient of other ion and vice versa,

Example:
Let suppose you are provided with A⁺² and B⁻¹, so multiply A by 1 and B by 2 as follow,
A(B)₂

In statement we are given with Co⁺³ and SO₄⁻², so multiply Co⁺³ by 2 and SO₄⁻² by 3, hence,

Co₂(SO₄)₃

Result:
Co₂(SO₄)₃ is the correct answer.

4 0

3 years ago

What is the atomic structure for antimony

djverab [1.8K]

Answer:

Hmm

Explanation:

Elemental antimony adults a layer structure (space group R3m No.166) in which layers consist of fused, ruffled, six-membered rings. The nearest and the next nearest neighbors form and irregular octahedral complex, with the 3 atoms in each layer slightly closer than 3 atoms in the next

Electric configuration : 4d^10 5s^2 5p^3

3 0

2 years ago

Which one of the following polymer is prepared by condensation polymerization?

nikitadnepr [17]

The answer is Darcon my friend, have a fantastic day

8 0

3 years ago

Read 2 more answers

You have 1 liter of a freshly prepared 0.1 m sucrose (molecular mass 342) solution, which means ________.

iris [78.8K]

1 liter of 0.1 M sucrose solution means that there is 34.2 g of sucrose dissolved in water to make a 1 liter solution. This also means that there are 6.022 × 10²² molecules of sucrose in this solution.

<h3>FURTHER EXPLANATION </h3>

Molarity is a unit of concentration which describes the number of moles of solute dissolved per liter of a solution. It is calculated using the equation below:

$molarity = \frac{moles \ of \ solute}{volume \ of \ solution}$

Molarity is expressed with the unit mol/L or M (read as “molar”). It is a very useful unit of concentration because many quantitative information about the solution can be obtained from this value.

<u>Mass of Solute from Molarity</u>

From the molarity of a solution, the equivalent mass of the solute used to prepare the solution may be obtained with the use of the formula mass (or molecular mass) through the equation:

$molarity = \frac{\frac{mass\ of \ solute}{formula \ mass}}{volume \ of \ solution}\\\\mass \ of \ solute \ = molarity \times \ volume \ of \ solution \times formula \ mass$

<u>Number of Representative Particles from Molarity</u>

Moreover, the number of molecules of solute present in the solution may also be obtained using the molarity and Avogadro's number.

$molarity = \frac{moles \ of \ solute}{volume \ of \ solution}\\\\no. \ of \ representative \ particles \ = molarity \times volume \times 6.022 \times 10^{23} \ representative \ particles$

For this problem, the mass of the solute dissolved in the solution and the number of sucrose molecules may be obtained from the molarity of the solution.

<em>Mass of Sucrose</em>

$mass \ of \ sucrose \ = 0.1 \ \frac{mol}{L} \times 1 \ L \times \frac{342 \ g \ sucrose}{1 \ mol}\\\\\boxed {\boxed {mass \ of \ sucrose = 34.2 \ g \ sucrose}}$

<em>Number of Sucrose Molecules</em>

<em> $no. \ of \ sucrose \ molecules \ = 0.1 \frac{mol}{L} \times 1 \ L \times \frac{6.022 \times 10^{23} \ sucrose \ molecules}{1 \ mol}\\\\\boxed {\boxed {no. \ of \ sucrose \ molecules \ = 6.022 \times 10^{22} \ molecules}}$ </em>