Answer:
5.27*10^23 (rounded to 3 significant figures)
Explanation:
The amount of molecules in one mole of anything is equal to Avogadro's number: 6.022×10^23
To find the number of moles of NaOH in 35 grams of it, do 35 divided by the molar mass (39.997): 35/39.997=0.87506562 moles of NaOH
To find the number of molecules, multiply the moles of NaOH by Avogadro's number: 0.87506562×(6.022×10^23)=5.26964522*10^23
In the KLMN electronic configuration style of writing K denotes the first shell which can hold up to two electrons, L denotes the second shell which can hold up to eight (2 + 6) or 8 electrons, M denotes the third shell which can hold up to eight (2 + 6 + 10) or 18 electrons etc.
The KLMN style of writing only indicates the number of electrons in each principal quantum number, however the spdf electronic configuration style of writing subdivides each shell into its subshells.
For instance the 3rd principal quantum number has s,p and d subshells, wherein s, p and d orbitals can have a maximum of 2, 6 and 10 electrons respectively.
The amino acid for this should be Arginine. I am not entirely sure.
Answer:
[H+] = 1.66 x 
Explanation:
To find the [H+] concentration of a solution, we can use the formula:
![[H+] = 10^{-pH}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%2010%5E%7B-pH%7D)
Let's plug in the pH.
![[H+] = 10^{-3.78}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%2010%5E%7B-3.78%7D)
Evaluate the exponent.
[H+] = 1.66 x
Hope this helps!
