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miss Akunina [59]
3 years ago
14

The pressure inside a compressed gas cylinder is 144 atm at 48°C. What will the pressure inside the cylinder be after it is cool

ed to 25°C? ?
a. 134 atm
b. 276 atm
c. No right choice.
Chemistry
1 answer:
Andrews [41]3 years ago
5 0
<h3>Answer:</h3>

134 atm

<h3>Explanation:</h3>
  • Based on the pressure law, the pressure of a gas varies directly proportionally to the absolute temperature at a constant volume.
  • Therefore; we are going to use the equation;

\frac{P1}{T1}=\frac{P2}{T2}

In this case;

Initial pressure, P1 = 144 atm

Initial temperature, T1 (48°C) = 321 K

Final temperature, T2 (25°C) = 298 K

We need to find the final pressure,

Therefore;

P2 = (P1/T1)T2

    = (144/321)× 298 K

    = 133.68 atm

   = 134 atm

Therefore, the new pressure will be 134 atm.

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Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,
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<u>Answer:</u> The empirical formula for the given compound is H_{4}O_1N_1Cl_1=H_4NOCl

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We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

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Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

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To formulate the empirical formula, we need to follow some steps:

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Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles

Moles of Chlorine = \frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = \frac{5.80}{1.44}=4.03\approx 4

For Oxygen = \frac{1.44}{1.44}=1

For Nitrogen = \frac{1.44}{1.44}=1

For Chlorine = \frac{1.44}{1.44}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is H_{4}O_1N_1Cl_1=H_4NOCl

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