Answer:
56
Step-by-step explanation:
corresponding angle to 56 is also opposite to x which means it is also 56
Answer:
21>a
Step-by-step explanation:
For inequalities, basically anything that uses > or < instead of an equal sign, you can generally treat it like an equality and use algebra. The only thing you have to look out for is if you multiply or divide by a negative. Then you have to flip the inequality sign. so < turns to > and > turns to < if you multiply or divide by a negative.
So first add one to both sides to get 14>(2/3)a
Then you can either divide both sides by (2/3) or do it in two steps by multiplying both sides by three and then dividing both side by 2, either way you get the same answer 21>a
I want to show you what happens if you multiply or divide by a negtive though. So instead of all that let's try making the first step subtracting (2/3)a from both sides to get 13-(2/3)a>-1.
Then we subtract 13 from both sides and get -(2/3)a>-14
Now, like before, we can divide both sides by -(2/3) or do it in two steps multiplying by 3 and then dividing by 2 to get -a>-21.
then to get a to a we multiply both sides by -1, now since we are multiplying by a negative the sign changes. so a>21 changes to a<21 which is the same as 21>a. let me know if you need any more help.
Answer:
y = 5; x = 1/5
Step-by-step explanation:
xy = 1 -----> x = 1/y
xy^2 = 5 -----> 1/y * y^2 = 5
y^2 / y = 5
y = 5
5x = 1
x = 1/5
Hope this Helps!
Answer:
Decision rule is
Fail to reject the null hypothesis
The conclusion is
There is sufficient evidence that indicate that there is a significant difference between the two treatments
Step-by-step explanation:
From the question we are told that
The sample size is n = 12
The first mean is ![M_1 = 55](https://tex.z-dn.net/?f=M_1%20%20%3D%20%2055)
The variance is ![s^2_1 = 8](https://tex.z-dn.net/?f=s%5E2_1%20%3D%20%208)
The second mean is
The second variance is ![s^2_2 = 4](https://tex.z-dn.net/?f=s%5E2_2%20%3D%20%204)
Let the level of significance be ![\alpha = 0.05](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%200.05)
The null hypothesis is ![H_o : M_1 = M_2](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20M_1%20%3D%20M_2)
The alternative hypothesis is ![H_a : M_1 \ne M_2](https://tex.z-dn.net/?f=H_a%20%20%3A%20%20M_1%20%5Cne%20M_2)
Generally the test statistics is mathematically
![t = \frac{M_1 - M_2 }{ \sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2}} }](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7BM_1%20-%20M_2%20%7D%7B%20%5Csqrt%7B%5Cfrac%7Bs_1%5E2%7D%7Bn_1%7D%20%2B%5Cfrac%7Bs_2%5E2%7D%7Bn_2%7D%7D%20%7D)
=> ![t = \frac{55 - 52 }{ \sqrt{\frac{8}{12} +\frac{4}{12 }} }](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B55%20-%2052%20%7D%7B%20%5Csqrt%7B%5Cfrac%7B8%7D%7B12%7D%20%2B%5Cfrac%7B4%7D%7B12%20%7D%7D%20%7D)
=>
Generally the degree of freedom is mathematically represented as
![df = 12 -1](https://tex.z-dn.net/?f=df%20%3D%2012%20-1)
=>
Generally from the t- distriibution table the critical value of
at a degree of freedom of
is
![t_{0.05 , 11} = 2.20098516](https://tex.z-dn.net/?f=t_%7B0.05%20%2C%2011%7D%20%3D%20%202.20098516)
Here given that the critical value is greater than the t statistics value the
Decision rule is
Fail to reject the null hypothesis
The conclusion is
There is sufficient evidence that indicate that there is a significant difference between the two treatments