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Pie
3 years ago
14

Right Triangle Trigonometry.

Mathematics
2 answers:
n200080 [17]3 years ago
8 0

Answer: D

Step-by-step explanation:

DiKsa [7]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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Under her cell phone plan, Lillian pays a flat cost of $47 per month and $3
anastassius [24]

Answer:

3.4 gigabytes

Step-by-step explanation:

Because 57.20$ divided by 47 is 10.20 and 3 goes in to 10.2 3.4 times.

3 0
3 years ago
This is soo hard please help
earnstyle [38]
It is going to decrease
8 0
4 years ago
Read 2 more answers
The population of Linton is 12 times as great as the population of Elmore the combined population of both towns is 9,646 people
AleksandrR [38]
9,646/13 (12+1) = 742, 742*12=8,904

Population of Elmore = 8,904
Population of Lintone = 742

enjoy

8 0
3 years ago
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
(7.3 x 10 to the power of 5 ) + 2,400,000 =
photoshop1234 [79]

7.3*10^+2,400,000

3130000

3 0
3 years ago
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