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Pie
3 years ago
14

Right Triangle Trigonometry.

Mathematics
2 answers:
n200080 [17]3 years ago
8 0

Answer: D

Step-by-step explanation:

DiKsa [7]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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Michael visited his grandparents.The total distance was 280 miles.By train,he could travel 90 miles per hour.By bus he could tra
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Michael could save about 95 minutes by taking the train.
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3 years ago
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
Pls help asapWhich of the q-values satisfy the following inequality?
Taya2010 [7]

Answer:

q=1 jeududhdhdhhdhhehd

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3 years ago
Math!!please help,its pretty easy.<br> 3*5-(1+10²)=
Ronch [10]

Answer:

-86

Step-by-step explanation:

3*5-(1+10^2)

15-(1+100)

15-101

-86

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3 years ago
Need help In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration
Shtirlitz [24]
S = at^2 + v0t + s0

at^2 = s - s0 - v0t

a = (s - s0 - v0t) / t^2
4 0
3 years ago
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