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Mnenie [13.5K]
3 years ago
11

Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.

Chemistry
2 answers:
k0ka [10]3 years ago
6 0

Answer:

Empirical Formula:

The empirical formula of a compound is the simplest whole-number ratio of the numbers of the different atoms that compose the molecule of the compound. The empirical formula looks like a molecular formula.

C

2

H

2

and

C

H

are the molecular formula and the empirical formula of acetylene.

The Given Data

The mass of carbon in the compound:

m

C

=

40.6

g

The mass of hydrogen in the compound: {eq}m_H = 5.1 \ \rm...

Sveta_85 [38]3 years ago
4 0

Answer: C4H6O, C2H3O2

Explanation:

C:H:O                                                            C2H3O2

40.6:5.1:54.2                                                (12x2) + (1x3) + (16x2) = 59

40.6/12 : 5.1/1 : 54.1/16                              118.1/59 =2     

3.38 : 5.1 : 3.38                                            C4H6O4

X (1:1.5:1) =

C2H3O2

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3 0
3 years ago
Hydrocarbons do not dissolve in concentrated sulfuric acid, but methyl benzoate does. Explain this difference and write an equat
finlep [7]

Answer:

See explanation

Explanation:

For a substance to dissolve in another, there must be some sort of interaction between the substances.

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In a percentage composition investigation a compound was decomposed into its elements: 20.0 g of calcium, 6.0 g of carbon, and 2
inysia [295]

The percentage composition of this compound : 40%Ca, 12%C and 48%O

<h3>Further explanation</h3>

Given

20.0 g of calcium,

6.0 g of carbon,

and 24.0 g of oxygen.

Required

The percentage composition

Solution

Total mass of compound :

=mass calcium + mass carbon + mass oxygen

=20 g + 6 g + 24 g

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Percentage composition :

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\tt \dfrac{20}{50}\times 100\%=40\%

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\tt \dfrac{6}{50}\times 100\%=12\%

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3 years ago
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