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Pani-rosa [81]
3 years ago
6

Hurry it’s for a test!! The arctic fox and gray wolf are two examples of

Chemistry
1 answer:
Lady_Fox [76]3 years ago
4 0
B
Protect themselves from predators
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Answer:

true

Explanation:

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You can cross multiply, it will be easy
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100 POINTS!!
elena55 [62]

Answer:

The correct matching of the air mass and the letters in the word bank are given as follows;

1. Warm and humid                   ↔       D

2. Extremely cold and dry        ↔       B

3. Cold and dry                         ↔       A

4. Cold and humid                    ↔       C

5. Warm and dry                       ↔        E

Where;

A Represents continental polar

B Represents Artic

C Represents Maritime Polar

D Represents Maritime Tropical

E Represents Continental Tropical

Explanation:

A. A continental polar is one that can be described as a cold and dry climate as the region is located at a further away from the oceanic water bodies that add humidity to the climate

B. The regions of the Artic and the Antarctic have very limited amount of precipitation every year because the air is very cold as well as dry

C. A polar climate is a cold climate region, while a maritime climate is humid.

Therefore, the maritime polar climate combines both cold and humid conditions

D. A warm and humid region has high rainfall and humidity, as such the maritime climate which are humid and the tropical climate, which are warm, combine to give a warm and humid climate

E. The continental tropical climate can be described as warm and dry, compared to the continental water bodies, due to the location being distant from and therefore, the absence of high moisture containing wind that comes from the oceans.

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3 years ago
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Carry out the following calculation, paying special attention to the significant figures (where 4/3 is exact), rounding, and uni
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Answer:

Value = 1.80 g/cm³ (Approx)

Explanation:

Given:

\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3}

Computation:

\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3} \\\\\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)} \\\\ \frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)}\\\\ \frac{3.39 \times 10^7g}{18.8166132\times 10^6 cm^3} \\\\ 1.80159945g/cm^3

Value = 1.80 g/cm³ (Approx)

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4 years ago
I really need help this is for a test I will give a lot of points.
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