Answer:
p = -5
every element in the sequence is created by subtracting 3 from the pervious element.
Step-by-step explanation:
I am not sure you put every necessary information here.
but I'd the visible information is truly everything, then it's is trivial.
the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.
we suspect this is the rule and keep trying.
1 -3 = -2
hey it works.
and -8 -3 = -11
hey, also correct.
and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.
therefore,
p = -2 -3 = -5
the rule is
an = an-1 - 3
300 grams = 0.3 kilograms
I would have to say A - Mean; because the data is skewed and there are outliers.
This is because the median of this would not be accurate for the number of kids that read no books and the random three kids that read ten. Mean, however, would find the true median within the plot and utilize and take into account the outliers and how skewed the data is.
Hope this helps!
8 - 7x^2 + 3 = 4x^2 - 1
8+3-7x^2 = 4x^2-1
11-7x^2 = 4x^2-1
B. Commutative property of addition
We can swap numbers and obtain the same results.
In this case, we swapped 8+3 and added them.
Answer:
52°
Step-by-step explanation:
<em>here's</em><em> </em><em>your</em><em> solution</em>
<em>=</em><em>></em><em> </em><em>we </em><em>know</em><em> </em><em>that</em><em> </em><em>the </em><em>measure</em><em> </em><em>of</em><em> </em><em>angle</em><em> of</em><em> </em><em>rectangle</em><em> </em><em>is </em><em> </em><em>9</em><em>0</em><em>°</em>
<em>=</em><em>></em><em> </em><em> </em><em>3</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>X </em><em> </em><em>=</em><em> </em><em>9</em><em>0</em><em>°</em>
<em>=</em><em>></em><em> </em><em>X </em><em>=</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>3</em><em>8</em><em>°</em>
<em>=</em><em>></em><em> </em><em>X </em><em>=</em><em> </em><em>5</em><em>2</em><em>°</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>