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atroni [7]
3 years ago
14

Calcula el tiempo que tarda en llegar a la Tierra la luz del sol si viaja a 300.000 km/s sabiendo que la distancia del sol a la

tierra es de 150.000.000 km. Exprésalo en minutos
Physics
1 answer:
Strike441 [17]3 years ago
5 0

Calculate the time it takes for sunlight to reach Earth if it travels at 300,000 km / s, knowing that the distance from the sun to the earth is 150,000,000 km. Express it in minutes

Answer:

8.3min

Explanation:

Given parameters:

Speed of sunlight  = 300000km/s

Distance of sun and earth  = 150000000km

Unknown:

Time in minutes  = ?

Solution:

To solve this problem;

     Speed  = \frac{distance }{time}  

 Time = \frac{distance}{speed}  

Now insert the parameters and find the speed;

  Time  = \frac{150000000}{300000}   = 500s

Now;

  60s makes 1 minute

 500s will give   \frac{500}{60}   = 8.3min

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What number and type of hybrid orbital(s) form(s) when one p and one s atomic orbital mix?
Harrizon [31]

Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

<h3>What are orbitals?</h3>

Orbital is the place around nucleus where mostly the electrons are present. There are four types of orbitals are present, s, p, d, and f.

The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.

Thus, two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

Learn more about orbitals

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3 0
3 years ago
An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, s
max2010maxim [7]

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

F_e=qE=ma             (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

x_{max}=v_o\sqrt{\frac{2d}{a}}             (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm

The horizontal distance traveled by the electron is 9.5cm

4 0
3 years ago
Given a sphere with radius r, find the height of a pyramid of minimum volume whose base is a square and whose base and triangula
BaLLatris [955]

Answer:

The Height of a pyramid is 4r.

Explanation:

Explanation is in the following attachments

6 0
3 years ago
D) cube
kondor19780726 [428]

Answer:

c because it makes since

Explanation:

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8 0
3 years ago
Read 2 more answers
Two trains approach each other on parallel tracks. Each has a speed of 95 kph relative to the ground. If they are initially 8.5
aliya0001 [1]

Answer: 2.83 minutes

Explanation:

It is understood that trains are approaching. That is, they have speeds of equal magnitude but opposite. When train A travels x meters northbound, then train B travels the same distance southbound.

Therefore trains approach at a speed of:

V = 95 +95 = 190\ km / h

Then:

V = \frac{x}{t}\\\\t = \frac{x}{V}

Where x is the distance between the trains

x = 8.5\ km

So the time in which both trains meet is:

t =\frac{8.5\ km}{180\ \frac{km}{h}}\\\\t=0.04722\ hours

This is:

0.04722*\frac{60\ minutes}{1\ hour} = 2.83\ minutes

<em />

<em>How long will it be before they reach one another ?</em>

<h3>2.83 minutes</h3>
3 0
3 years ago
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