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natima [27]
4 years ago
11

What is ohms law for science

Physics
2 answers:
dexar [7]4 years ago
5 0

Answer:

Explanation:

According to ohm's law

The current flowing through the wire is directly proportional to the potential difference applied across its ends , provided the temperature and other physical conditions of the wire like stresses and strains remains constant .

ipn [44]4 years ago
5 0
A law relating the voltage difference between two points, the electric current flowing between them, and the resistance of the path of the current. Mathematically, the law states that V = IR, where V is the voltage difference, I is the current in amperes, and R is the resistance in ohms. For a given voltage, higher resistance entails lower current flow.
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5. How many kilowatt-hours of energy would be used by a 40 W bulb that runs for 10 hours every
Nady [450]

Answer:

E = 0.4 kWh

Explanation:

Given that,

The power of a bulb, P = 40 W

Time, t = 10 hours

We need to find the energy used by the bulb. Let it is equal to E. So,

E=P\times t\\\\E=40\times 10\\\\E=400\ W-h\\\\or\\\\E=0.4\ kWh

So, 0.4 kWh of energy would be needed.

6 0
3 years ago
If a box weighs 20 newtons, will a force of 20 newtons push it?
WITCHER [35]
No. A greater force must push it
8 0
4 years ago
What determines the type of the image formed after refraction from a convex lens?
saw5 [17]
C. position of the object
Hope it helps! :)
8 0
4 years ago
Read 2 more answers
Find the frequency of a tuning fork that takes2.50×10−3s to complete one oscillation.
maksim [4K]

The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.

Frequency = 1/time period of the oscillation

Frequency of the tuning fork = 1/time period

                                                   =1/2.50×10⁻³

                                                   =400 Hz

Thus the frequency of a tuning fork comes out to be 400 Hz.

Learn more about frequency here, refer to the link;

brainly.com/question/14316711

#SPJ1

6 0
2 years ago
An electron is accelerated from rest by a potential difference of (24.5 A) V for a distance of (4.50 B) cm. Determine the de Bro
DiKsa [7]

Answer:

206 pm

Explanation:

We are given that

Potential difference,\Delta V=24.5+A V

Distance,d=4.5+B cm

We have to determine the de Brogile wavelength of the electron.

A=11 and B=5

\Delta V=24.5+11=35.5 V

d=4.5+5=9.5 cm

Charge on electron,q =1.6\times 10^{-19} C

Mass of electron=m=9.1\times 10^{-31} kg

Speed of electron,v=\sqrt{\frac{2q\Delta V}{m}}

Using the formula

v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 35.5}{9.1\times 10^{-31}}

v=3.53\times 10^6 m/s

de Brogile wavelength, \lambda=\frac{h}{mv}

Where h=6.626\times 10^{-34}

\lambda=\frac{6.626\times 10^{-34}}{9.1\times 10^{-31}\times 3.53\times 10^6}=2.06\times 10^{-10}=206\times 10^{-12} m

1 pm=10^{-12} m

\lambda=206 pm

7 0
3 years ago
Read 2 more answers
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