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elena-14-01-66 [18.8K]
3 years ago
6

13.

Physics
1 answer:
sattari [20]3 years ago
7 0

13) concentration

14) amino acids

15) passive transport

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Use the following table to calculate the train's average velocity during part B of the train ride.​
anyanavicka [17]

Answer:

60km/hr due east

Explanation:

Given parameters:

Displacement = 60km East

Start time  = 10am

End time  = 11am

Unknown:

Average velocity  = ?

Solution:

The average velocity is the displacement divided by the time taken.

 For this journey, the time taken is;

              11am  -  10am  = 1hr

 So;  

 Average velocity  = \frac{60km}{1hr} = 60km/hr due east

6 0
3 years ago
Can anyone plz answer this?
Scrat [10]

Answer:

I would say C

Explanation:

A is a steep or about 45° angle while B appears to be a straight down angle of 0°. So if you take that into account, if you are subtracting A and B, it would be around in between. It will probably not be backwards because neither is facing to the left except the answer choices so B is wrong (the answer B).

R is even steeper than before, and if you are subtracting, it would probably be C.

7 0
3 years ago
A=i+j-k<br>b=j+k<br><img src="https://tex.z-dn.net/?f=a%20%3D%20i%20%2B%20j%20-%20k%20%20%20%5C%5C%20b%20%3D%20j%20%2B%20k" id="
olga nikolaevna [1]

Answer:

¿

Explanation:

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4 0
3 years ago
Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes
Nina [5.8K]

Answer:

Δλ = 3*10⁻³ m.

Explanation:

  • At any wave, there exists a fixed relationship between the speed of  the wave, the wavelength, and the frequency, as follows:

       v = \lambda* f  (1)

       where v is the speed, λ is the wavelength and f is the frequency.

  • Rearranging terms, we can get λ from the other two parameters, as follows:

       \lambda = \frac{v}{f}  (2)

  • Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:

        \lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m  (3)

        \lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m  (4)

  • The difference between both wavelengths, is just the difference between (3) and (4):

       \Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)

       ⇒ Δλ = 3*10⁻³ m.

6 0
3 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the play
Alona [7]

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

4 0
3 years ago
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