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Schach [20]
4 years ago
14

Help don't answer if you don't know​

Mathematics
1 answer:
Dmitry [639]4 years ago
7 0

Answer:

not 100% confident but I think this is at least close

Step-by-step explanation:

solve for one variable

1. x-5y=2

x=2+5y

plug this in to another equations and simplify

2. (2+5y)-y=16

2+4y=16

4y=14

y=3.5

this can be plugged in to all other equations to find x

1. x-5(3.5)=2

x-17.5=2

x=19.5

2. x-(3.5)=16

x=19.5

3. 2x-(3.5)=5

2x=8.5

x=4.25

4. x-3(3.5)=4

x-10.5=4

x=14.5

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a) y+6x=5 if x= -1  then y+6(-1)=5 then y = 11
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Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

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(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

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We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

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