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Vlad1618 [11]
3 years ago
6

What mass of Cu(s) is electroplated by running 24.5A of current through a Cu2+(aq)solution for 4.00 h?Express your answer to thr

ee significant figures and include the appropriate units.
Chemistry
1 answer:
Masja [62]3 years ago
8 0

Answer: 116 g of copper

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 24.5A

t= time in seconds =  4.00 hr = 4.00\times 3600s=14400s  (1hr=3600s)

Q=24.5A\times 14400s=352800C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500C=193000C  of electricity deposits 63.5 g of copper.

352800 C of electricity deposits = \frac{63.5}{193000}\times 352800=116g of copper.

Thus 116 g of Cu(s) is electroplated by running 24.5A of current

Thus  remaining in solution = (0.1-0.003)=0.097moles

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Explanation:

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The element whose atoms or molecules contain orbitals that are all filed up with paired electron is diamagnetic.

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4 years ago
What is the density of a piece of wood that has a mass of 35.0 grams and a volume of 26.4 cm3
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Answer:

We have the final answer as

<h2>1.33 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass = 35 g

volume = 26.4 cm³

The density of the wood is

density =  \frac{35}{26.4}  \\ 1.325757575757...

We have the final answer as

<h3>1.33 g/cm³</h3>

Hope this helps you

3 0
3 years ago
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t-Butyl alcohol (TBA) is an important octane enhancer that is used to replace lead additives in gasoline [Ind. Eng. Chem. Res.,
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Complete Question:

t-Butyl alcohol (TBA) is an important octane enhancer that is used to replace lead additives in gasoline [Ind. Eng. Chem. Res., 27, 2224 (1988)]. TBA was produced by the liquid-phase hydration (W) of isobutene (I) over an Amberlyst-15 catalyst. The system is normally a multiphase mixture of hydrocarbon, water, and solid catalysts. However, the use of cosolvents or excess TBA can achieve reasonable miscibility. The reaction mechanism is believed to be

I + S ⇄ I*S

W + S ⇄ W*S

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TBA * S ⇄ TBA + S

Derive a rate law assuming:

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(b) The adsorption of isobutene is limiting

(c) The reaction follows Eley-rideal Kinetics

I*S+W ⇄ TBA * S

and surface reaction is limiting

(d) Isobutene (I) and water (W) are adsorbed on different sites

I + S₁ ⇄ I*S₁

W + S₂ ⇄ W*S₂

TBA is not on the surface, and the surface reaction is rate-limiting

[Ans: r'_{TBA}=-r'_1=\frac{k[C_1C_w-C_{TBA/K_C}]}{(1+K_WC_W)(1+K_1C_1)} ]

(e) What generalizations can you make by comparing rate laws derived from part (a) through (d)?

Answer and explanation:

The mechanism for the production of t-butyl alcohol is as follows:

the reaction and rate law for the adsorption of isobutene over the amberlyst-15 is as follows:

I + S ⇄ I * S                                        -r_{ADI} = k_I(C_1C_v-\frac{C_{I.S}}{K_I} )

where C_V is the concentration of vacant site

K_I is the equilibrium constant of the adsorption

k_I is the rate constant for forward

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The reaction and rate law for the adsorption of water (W) over the amberlyst-15 catalyst catalyst is as follows

W + S ⇄ W.S                                      -r_{ADW} = k_W(C_WC_V-\frac{C_{W.S}}{K_W} )

The reaction and rate law for the surface reaction on the catalyst is as follows

W.S + I.S ⇄ TBA . S + Sn                         -r_s = k_s(C_{W.S}C_{I.S}-\frac{C_{TBA.S}C_V}{K_s} )

The reaction and rate law for the desorption of TBA from catalyst is as follows

TBA . S ⇄ TBA + S                             -r_{D TBA} = k_{DTBA}(C_{TBA.S}-\frac{C_{TBA}C_V}{K_{DTBA}} )

the attached image below gives the remaining steps    

5 0
3 years ago
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