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ella [17]
4 years ago
8

In your own words what is equilibrium?

Chemistry
1 answer:
fenix001 [56]4 years ago
8 0

Answer:

when the forward and reverse reactions occur at equal rates.

chemical reaction is in equilibrium when the concentrations of reactants and products are constant - their ratio does not vary.

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What causes the high luster of a metal?
Karo-lina-s [1.5K]

Answer:

When light is shone on to the surface of a metal, its electrons absorb small amounts of energy and become excited into one of its many empty orbitals. The electrons immediately fall back down to lower energy levels and emit light. This process is responsible for the high luster of metals.

Explanation:

<em> </em><em>Your </em><em>well-wisher</em><em> </em><em>:-)</em>

7 0
3 years ago
Đơn chất nào sau đây tác dụng với dung dịch axit sunfuric loãng sinh ra khí ?
viva [34]

Answer:

C. Al

Explanation:

2Al+ 3H2SO4(l)------> Al2(SO4)3+ 3H2

6 0
3 years ago
CH4(g)+O2(g)→CO2(g)+H2O(g). What mass of water is produced from the complete combustion of 5.00×10−3 g of methane?
bixtya [17]

Answer:

1gram of water

Explanation:

First balance the equation

Ch4+2O2>CO2+2H2O

Ratio is 1:2

500×10-3what about 2?

500×10-3×2=1g

1g of water

4 0
3 years ago
The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
4 years ago
If two atoms have an electronegativity difference of 1.3, what type of bond would form between them?
Debora [2.8K]

Answer:

The correct answer is b polar covalent

Explanation:

When two atoms joined by covalent bond has difference in their electronegativities at that time polarity arise.

    When the electronegativity difference is low such as 1.3 then the polar bond formed by the two atoms are called polar covalent bond.For example H2O

 on the other hand polar bond formed by two atoms having high difference in their electronegativities is called ionic bond.For example NaCl.

5 0
3 years ago
Read 2 more answers
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