Answer:
Please find attached the completed Lewis dot diagram structure for PI₂F
Explanation:
The number of valence electrons are;
Phosphorus = 5 Electrons
Iodine = 2 × 7 electrons = 14 electrons
Chlorine = 7 electrons
The total number of valence electrons = 14 + 7 + 5 = 26 electrons
2) We draw the symbol that represents the basic (general) structure of the molecule as follows;
The sheared electron pair are represented by single bond lines
3) We complete the octet structures round the fluorine and the iodine atoms as attached showing 18 electrons plus 6 shared electron pairs, with a maximum from step 2 to give a total of (18 + 6) 24 electron pairs
4) We add the 2 unaccounted valence electron on the phosphorus atom to give it the stable octet structure, which gives the completed Lewis structure
Answer:
P_2 =0.51 atm
Explanation:
Given that:
Volume (V1) = 2.50 L
Temperature (T1) = 298 K
Volume (V2) = 4.50 L
at standard temperature and pressure;
Pressure (P1) = 1 atm
Temperature (T2) = 273 K
Pressure P2 = ??
Using combined gas law:
<u>Answer:</u>
It is the expression of Charles' Law.
<u>Explanation:</u>
The given expression V1T2 = V2T1 is the formula for the Charles' Law.
A special case of an ideal gas is named as the Charles' Law. This law applies to ideal gases only which are at constant pressure.
According to this law, the volume of a fixed mass of a gas is directly proportional to its temperature and is given by:
V1T2 = V2T1
Answer:
<h2>The mosquitoes like when its wet and moist than dry temp.</h2>
Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :
[butane]=1.0 M , [isobutane]=2.5 M
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?
Answer:
The equilibrium concentration of each gas:
[Butane] = 1.14 M
[isobutane] = 2.86 M
Explanation:
Butane ⇄ Isobutane
At equilibrium
1.0 M 2.5 M
After addition of 0.50 M of butane:
(1.0 + 0.50) M -
After equilibrium reestablishes:
(1.50-x)M (2.5+x)
The equilibrium expression will wriiten as:
![K_c=\frac{[Isobutane]}{[Butane]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BIsobutane%5D%7D%7B%5BButane%5D%7D)
x = 0.36 M
The equilibrium concentration of each gas:
[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M
[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M
