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3 years ago

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Find the mass in 34.4 liters of O2 gas at STP?

1 answer:

drek231 [11]3 years ago

8 0

Answer:

mass of 1 mole of 34.4liters, O2, STP = 95.039999g

Explanation:

Write the problem as a mathematical expression.

Find the mass in 34.4liters of O2 gas at STP

To find the mass of 1 mole of 34.4liters, O2, STP look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of 1 mole of 34.4liters, O2, STP = 2(mass of O) + (mass of S) + (mass of T) + (mass of P)

Fill in the atomic masses from the periodic table.

mass of 1 mole of 34.4liters, O2, STP = 2(16) + (32.06999969) + (0) + (30.96999931)

Simplify the result.

mass of 1 mole of 34.4liters, O2, STP = 95.039999g

<em>hope this helps, good luck :)</em>

also ive got no clue why the spacing looks all funny, sry about that

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A chemist wants to extract a solute from 100 mL of water using only 300 mL of ether. The partition coefficient between ether and

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Answer:

a. 0,903

b. 0,985

c. 0,996

Explanation:

Partition coefficient between ether and water is:

$K = \frac{CONCether}{CONCwater}$

a. As k = 3,10, a single extraction with 300mL ether will give:

$3,10 = \frac{(q/300mL)}{(1-q)/100mL}$

9,30 - 9,30q = q

9,30 = 10,30q

<em>q = 0,903</em>

b. Three extractions of 100 mL will extract:

First extraction:

$3,10 = \frac{(q/100mL)}{(1-q)/100mL}$

3,10 - 3,10q = q

3,10 = 4,10q

<em>q = 0,756</em>

The second extraction will 0,756 times of the solute that is in water. This solute is 1-0,756=0,244

Second extraction will extract 0,244*0,756 = <em>0,184</em>

In the same way, third extraction will extraxt: (0,244-0,184)*0,756 = <em>0,045</em>

Total solute extracted:

<em>q = 0,756 + 0,184 + 0,045 = 0,985</em>

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c. Six extractions with 50mL of ether extract:

First extraction:

$3,10 = \frac{(q/50mL)}{(1-q)/100mL}$

3,10 - 3,10q = 2q

3,10 = 5,10q

<em>0,608 = q</em>

Second extraction = (1-0,608)*0,608 = 0,234

Third extraction =(1-0,608-0,234)*0,608 = 0,096

Fourth extraction =(1-0,608-0,234-0,096)*0,608 = 0,038

Fifth extraction =(1-0,608-0,234-0,096-0,038)*0,608 = 0,015

Sixth extraction =(1-0,608-0,234-0,096-0,038-0,015)*0,608 = 0,005

q = 0,608+0,234+0,096+0,038+0,015+0,005 = <em>0,996</em>

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I hope it helps!

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