How many moles of nitrogen gas will occupy a volume of .5L at 1.0atm and 298K

1 answer:

8 0

Use the Ideal law Equation :

P.V= n.R.T

V = 0.5 L

P = 1.0 atm

R= 0.0821 L*atm/mol*K

n = R*T/P*V

P*V= n*R*T

1.0 * 0.5 = n *0.0821*298

0,5 = n* 24.4658

n = 0,5 / 24.4658

n =0.0204 moles

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