All categories

3 years ago

How many moles of nitrogen gas will occupy a volume of .5L at 1.0atm and 298K

1 answer:

8 0

Use the Ideal law Equation :

P.V= n.R.T

V = 0.5 L

P = 1.0 atm

R= 0.0821 L*atm/mol*K

n = R*T/P*V

P*V= n*R*T

1.0 * 0.5 = n *0.0821*298

0,5 = n* 24.4658

n = 0,5 / 24.4658

n =0.0204 moles

You might be interested in

PLEASE HELP!!! Which type of substance is gold an example of?

dmitriy555 [2]

Answer:

Hello!

Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal. Chemically, gold is a transition metal and a group 11 element.

So in short, the Correct Answer will be (D) an Element.

Hope that Helps! Have A Wonderful Day! ☺

Explanation:

7 0

2 years ago

Read 2 more answers

5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements

love history [14]

B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

Total pressure and partial pressure

Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

P Nitrogen = 1/3 x 303.975 = 101.325 kPa

P Hydrogen = 2/3 x 303.975 = 202.65 kPa

7 0

3 years ago

If the molecule C6H12 does not contain a double bond, and there are no branches in it, what will its structure look like?

NARA [144]

I have attached a photo of the structure.
You can get better at solving problems like this by practicing a lot!

5 0

3 years ago

Balance this equation and pick the answer with the coefficients that belong there.

geniusboy [140]

Answer:

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃

Conserving Al; a = 2d

Br: 3a = c

K: 2b = c

S: b = 3d

O: 4b = 12d

Let a = 1, c = 3, d = $\frac{1}{2}$ b = $\frac{3}{2}$

Multiply through by 2 to give;

a = 2, b = 3, c = 6 and d = 1

2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃

6 0

2 years ago

Calculate the mass of 6 moles of H2O

RUDIKE [14]

6mole of H2O contains 18×6 g=108 g

8 0

3 years ago

Read 2 more answers