Determine the molecular formula of a compound that has a molar mass of 183.2 g/mol and an empirical formula of c2h5o2.
2 answers:
Answer:
Explanation:
Hello,
In this case, one computes the molar mass for the given empirical formula as follows:
In such a way, one computes how many times the molecular formula's molecular mass is contained into the empirical formula's molecular mass in order to determine the whole number relating them as shown below:
Finally, the molecular formula is three times the empirical formula, hence:
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Answer: 3.72 M
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = age of sample = 15.0 minutes
a = let initial amount of the reactant = 10.0 M
a - x = amount left after decay process = ?
The concentration of in a solution after 15.0 minutes have passed is 3.72 M
Based on the chemical equation, 4 moles of lithium reacts with 1 mole of oxygen to produce 2 moles of lithium oxide.
First of all you need to find 1 mole of Lithium by diving 1.68 mol by 4 and the answer should be 0.42 mol. To calculate the no. of moles of lithium oxide, you've to multiply 0.42 mol by 2. Hence the answer, 0.84 mol.
First of all you need to find 1 mole of Lithium by diving 1.68 mol by 4 and the answer should be 0.42 mol. To calculate the no. of moles of lithium oxide, you've to multiply 0.42 mol by 2. Hence the answer, 0.84 mol.