Question

Determine the molecular formula of a compound that has a molar mass of 183.2 g/mol and an empirical formula of c2h5o2.

Answer 1

Answer:

$C_6H_{15}O_6$

Explanation:

Hello,

In this case, one computes the molar mass for the given empirical formula as follows:

$M_{empirical}=12*2+1*5+16*2=61g/mol$

In such a way, one computes how many times the molecular formula's molecular mass is contained into the empirical formula's molecular mass in order to determine the whole number relating them as shown below:

$\frac{183.2g/mol}{61g/mol}=3$

Finally, the molecular formula is three times the empirical formula, hence:

$C_6H_{15}O_6$

Best regards.

Answer 2

C6H15O6

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