Answer:
im not doing your whole homework. but ill give you one cent ;>, whats ur paypal
Explanation:
The molality of the solution = 17.93 m
<h3>Further explanation</h3>
Given
6.00 L water with 6.00 L of ethylene glycol(ρ=1.1132 g/cm³= 1.1132 kg/L)
Required
The molality
Solution
molality = mol of solute/ 1 kg solvent
mol of solute = mol of ethylene glycol
- mass of ethylene glycol :
= volume x density
= 6 L x 1.1132 kg/L
= 6.6792 kg
= 6679.2 g
- mol of ethylene glycol (MW=62.07 g/mol)
=mass : MW
=6679.2 : 62.07
=107.608
6 L water = 6 kg water(ρ= 1 kg/L)
The molecule is the representative particle of molecular compounds. It is also the representative particle of diatomic elements.
<h2>
I hope this helps you, have a beautiful day ✨</h2>
The question is incomplete, the complete question is; Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2.2H2O
Answer:
See explanation
Explanation:
First we must know the molar mass of the compound = 244.3 g/mol
Now we must calculate the number of moles of BaCl2.2H2O in the solution.
number of moles = concentration * volume = 0.108 M * 2.00 L = 0.216 moles
Now the mass of solid that we need to take can be obtained from;
number of moles = mass/molar mass
mass = number of moles * molar mass
mass = 0.216 moles * 244.3 g/mol
Mass = 52.8 g
Hence, we must weigh 52.8 g of BaCl2.2H2O accurately in a balance and dissolve it in 2 L of water to give 0.108 M solution of BaCl2.2H2O.
Le Chatelier's Principle says that when something disrupts the equilibrium, the system adjusts to minimize the effect of that disturbance. If 0.1 M HCl solution is added, this dissociates into H+ and Cl- ions, so there will be more Cl- ions in the system. This causes the reaction to go in the reverse direction (equilibrium shifts to the left) to reduce the amount of Cl-.
Since this also consumes Ag+ ions, the concentration of Ag+ (aq) will decrease.
The answer is the second choice.
