The type of bond between two elements can be predicted by measuring the electronegativity difference between the two atoms. Based on this difference the type of bonds are classified as,
E.N difference between 0.0 to 0.3 = Non Polar bond
E.N difference between 0.4 to 1.0 = Moderate Polar Covalent Bond
E.N difference between 1.1 to 2.0 = Very Polar Covalent Bond
E.N difference greater than 2.0 = Ionic Bond
So,
(E.N of N) 3.04 - (E.N of C) 2.55 = 0.49
As the difference is between 0.4-1.0, So, the bond between C and N is Moderate Polar Covalent Bond (or Polar Covalent Bond).
Answer:
(B) 3
Explanation:
Citric acid has an acid dissociation constant (Ka) of 8.4 × 10⁻⁴. When it forms a buffer with its conjugate base (citrate), we can calculate the pH using the Henderson-Hasselbalch's equation.
![pH=pKa+log\frac{[base]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
The optimum range of pH is pKa ± 1. The pKa is -log Ka = -log (8.4 × 10⁻⁴) = 3.1. The buffer would be more effective for pH between 2.1 and 4.1, especially around 3.1. So the best choice is (B) 3.
An atom's electronegativity is affected by both its atomic number and the size of the atom. The higher its electronegativity, the more an element attracts electrons. The opposite of electronegativity is electropositivity, which is a measure of an element's ability to donate electrons.
Don’t understand lol... but I’m chasing those points so thanks