Answer:
semipermeability
Explanation:
partially but not freely or wholly permeable specifically : permeable to some usually small molecules but not to other usually larger particles a semipermeable membrane.
To solve this we assume that the gas is an ideal
gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At
a constant temperature and number of moles of the gas the product of PV is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
<span>V2 = 153 x 4 / 203</span>
V2 = 3 L
Answer:
4–ethyl–2,3–dimethylheptane
Explanation:
To name the compound given above, do the following:
1. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest continuous carbon chain is 7. Thus the parent name is Heptane.
2. Identify the substituent group attached to the compound. In this case, the substituent group attached are:
a. Methyl (–CH₃). There are two methyl group attached.
b. Ethyl (–CH₂CH₃)
3. Locate the position of the substituent group attached to the compound by naming alphabetically.
a. The two Methyl (–CH₃) groups are located at carbon 2 and 3
b. The Ethyl (–CH₂CH₃) is located at carbon 4.
NOTE: The position of the Ethyl (–CH₂CH₃) group is the same from both side so we consider the lowest count for the methyl group.
4. Combine the above to obtain the name of the compound.
The name of the compound is:
4–ethyl–2,3–dimethylheptane
Answer:
<em>What quantity dictates the speed of a reaction?</em> The activation energy
Explanation:
According to the collision theory, when molecules collide, they must overcome an energy barrier for the reaction to take place. This energy, known as activation energy, is represented by the difference in energy between the initial state and the transition state. The higher the activation energy, the slower the reaction. That's why catalysts reduce the activation energy to accelerate the reaction.
Answer:
According to stoichiometry :
2 moles of
produce = 4 moles of
gas and 1 mole of
gas
2 moles of
produce = 5 moles of gas
Thus 0.1 mole of
produce =
of gas
Volume of gas produced =
Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.