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spayn [35]
2 years ago
7

What happens to the potential energy of an object when it falling from a high place?

Chemistry
1 answer:
Juliette [100K]2 years ago
7 0

Answer:

The higher up an object is the greater its gravitational potential energy. ... As most of this GPE gets changed into kinetic energy, the higher up the object starts from the faster it will be falling when it hits the ground. So a change in gravitational potential energy depends on the height an object moves through.

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What do greenhouse gases do in our atmosphere?
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Greenhouse gases are gases in Earth's atmosphere that trap heat. They let sunlight pass through the atmosphere, but they prevent the heat that the sunlight brings from leaving the atmosphere.

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Which group has eight valence electrons?
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16 grams of propane, C 3 H 8 and 20 grams of oxygen, O 2 are reacted to produce carbon dioxide and water. Calculate the volume o
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Answer:

The volume of CO₂ produced is 8.4 L

Explanation:

The mass of propane in the reaction C₃H₈ = 20 grams

The mass of, oxygen, O₂ in the reaction = 20 grams

The produce of the reaction are carbon dioxide, CO₂ and water, H₂O

The balanced equation of the (combustion) reaction can be presented as follows;

C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)

Therefore, one mole of propane, C₃H₈, reacts with five moles of oxygen, O₂, to produce three moles of carbon dioxide, CO₂, and four moles of water molecules, H₂O, as steam

The number of moles = Mass/(Molar mass)

The molar mass of propane, C₃H₈ = 44.1 g/mol

The number of moles of propane in 16 grams of propane = 16/44.1 ≈ 0.3628 moles

The molar mass of oxygen, O₂ = 32.0 g/mol

The number of moles of oxygen in 20 grams of propane = 20/32 ≈ 0.625 moles

Therefore;

Given that 1 mole of C₃H₈ reacts with 5 moles of O₂

1 mole of O₂ will react with 1/5 moles of C₃H₈

0.625 moles of O₂ will react with 0.625/5 = 0.125 moles of C₃H₈ to produce 3 × 0.125 = 0.375 moles of CO₂

1 mole of an ideal gas occupies 22.4 L at standard temperature and pressure

Taking CO₂ as an ideal gas, we have;

0.375 mole of CO₂ will occupy 0.375 × 22.4 L = 8.4 L

Therefore, the volume of CO₂ produced = The volume occupied by the 0.375 moles of CO₂ = 8.4 L.

5 0
2 years ago
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Answer:

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Explanation:

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