well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)
![f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cbegin%7Bcases%7D%207x%2Bk%2C%26x%5Cleqslant%202%5C%5C%20kx%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%282%29%3D%20%5Cbegin%7Bcases%7D%207%282%29%2Bk%2C%26x%5Cleqslant%202%5C%5C%20k%282%29%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%207%282%29%2Bk~~%20%3D%20~~k%282%29%5E2-6%5Cimplies%2014%2Bk~~%20%3D%20~~4k-6%20%5C%5C%5C%5C%5C%5C%2014~~%20%3D%20~~3k-6%5Cimplies%2020~~%20%3D%20~~3k%5Cimplies%20%5Ccfrac%7B20%7D%7B3%7D%3Dk)
Answer:
B) Likely
Step-by-step explanation:
Unlikely = < 50%
Likely = > 50%
Certain = 100%
Equally likely = 50%
We can make two simple equations to express their ages to each other, then solve for one of the variables. Let n be Nojo's age and j be Jacob's age.
n(j) = 84
n - 5 = j
Use substitution to get only one variable in an equation.
n (n - 5) = 84
n^2 - 5n = 84
Since we have n to the power of 2, this equation has two possible answers, but since we are given four possible answer, just substitute them in the equation until one makes the left side equal 84.
<span>n^2 - 5n = 84
</span>12^2 - 5 (12) = 84
144 - 60 = 84
84 = 84
The answer is C = 12
First subtract 100v² from both sides to get:
C²L²=100c²-100v²
Then divide both sides by C²:
L²=(100c²-100v²)/C²
Then take the square root of both sides:
L=+ or - the square root of (100c²-100v²)/C²
Answer:
to what
Step-by-step explanation:
