IF YOU HAVE A BUILDING THAT IS 32' WIDE, AND

Mathematics

2 answers:

Gemiola [76]3 years ago

5 0

Answer:

1600

Step-by-step explanation:

Dima020 [189]3 years ago

4 0

Answer:

Approximately 1,600 sq ft

Step-by-step explanation:

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vlada-n [284]

G(-3)= 2(-3)-22=-28

This is the correct answer

7 0

3 years ago

Jane needs $20 to buy her radio. She has saved $15.

KonstantinChe [14]

Answer:

the answer is d

Step-by-step explanation:

$\frac{15}{20} \times 100 = 75$

7 0

3 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$