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3 years ago

Help plz:))) I’ll mark u brainliest ASAP 10 points(:(: Xx thank you....!!!

Mathematics

1 answer:

Hunter-Best [27]3 years ago

7 0

Answer:

Step-by-step explanation:

D because K to M is the shortest line in the diagram. Please mark brainllest if you want you dont have to.

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How many different outcomes can happen from spinning a four-section spinner twice, according to the diagram given?

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3 years ago

1 28<br> 3 <br> 140<br> fill in the blanks

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3 years ago

SOMEONE PLEASE HELP!!! [ 20 POINTS] SERIOUS ANSWERS ONLY!!!!

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3 years ago

Read 2 more answers

Find the circumference and the area of a circle with radius 3 m.

Effectus [21]

Answer:

$\boxed {c= 18.84 \ m}$

$\boxed {a=28.26 \ m^2}$

Step-by-step explanation:

We are asked to find the circumference and area of a circle with a radius of 3 meters.

<h3>1. Circumference </h3>

The circumference is the perimeter of a circle. It is calculated using the following formula:

$c= \pi d$

We know the radius of the circle is 3 meters, but we must find the radius. The radius is the line from the center to the circle's edge, while the diameter is the line through the center from edge to edge. Therefore, the diameter is twice the radius.

d= 2 r
d= 2 * 3 m
d= 6 m

The diameter is 6 meters and we are using 3.14 for pi. Substitute these values into the circumference formula.

$c= (3.14)(6 \ m )$

Multiply.

$\bold {c= 18.84 \ m}$

The area is the size of the circle's surface. It is calculated using the following formula.

$a= \pi r^2$

The radius is 3 meters are we are using 3.14 for pi. Substitute these values into the area formula.

$a= (3.14)(3 \ m)^2$

Solve the exponent.

(3 m)² = (3 m)(3 m)= 9 m²

$a= (3.14)(9 \ m)^2$

$\bold {a=28.26 \ m^2}$

The circumference is 18.84 meters and the area is 28.26 square meters.

6 0

3 years ago

Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec

Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

C. 0.010 < P-value < 0.025

b. Power of test = 1- β=0.2066

c. So the sample size is 88

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test

Here n= 7 and significance level ∝= 0.005

Critical value for a right tailed test with 6 df is 1.9432

Sample Standard deviation = s= 32

Sample size= n= 7

Sample Mean =x`= 630

Degrees of freedom = df = n-1= 7-1= 6

The test statistic used here is

Z = x- x`/ s/√n

Z= 630-600 / 32 / √7

Z= 2.4797= 2.48

P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

hypothesis mean = 600

standard deviation= 32

power = β=0.9

Z∝= 1.645

Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n= ((1.645+1.282) 32/ 10)²

Putting the values and solving we get 87.69

So the sample size is 88

5 0

3 years ago