Square root of (675 b^3 c^2 d^4 )
Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Answer:
B, 224in2
It may get tedious but just find the area of each face and write them down
Step-by-step explanation:
The LCD of 24 and 23 is 552, so 276/552 - 240/552 = 36. After simplifying 36/552, you get 3/46 and that is your answer.
Answer:
51.0791%
Step-by-step explanation:
Calculate percentage change
from V1 = 41700 to V2 = 63000
(V2−V1)|V1|×100
=(63000−41700)|41700|×100
=2130041700×100
=0.510791×100
=51.0791%change
=51.0791%increase
