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barxatty [35]
3 years ago
15

Describe two characteristics that can be determined about a star by analyzing the spectra of the star.

Physics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

Effective temperature, Doppler velocity

Explanation:

Since star behave localy as a blackbody, Wíen's displacement law can be use in order to determine its effective temperature. From the spectrum it will be take the wavelength at which is the peak of emission greater in the continuum

 

Then, the maximum peak of emission (\lambda_{max}) will be replace in the next equation of the Wien's displacement law:

T = \frac{2.898x10^{-3} m. K}{\lambda max} (1)

Where T is the effective temperature of the star.

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

By using that shift in the spectral lines it can be determine the Doppler velocity.

v = c\frac{\Delta \lambda}{\lambda_{0}}  (2)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

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What class lever is a
Alchen [17]

should be 1

Explanation:

because what do you use in class and has a lever

8 0
3 years ago
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.
galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s

v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s

<u>Time taken to reach 1180 m is 11.29 seconds</u>

v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s

<u>Time the rocket will keep going up after the engines shut off is 13.06 seconds.</u>

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s

<u>Time taken by the rocket to fall from maximum height is 20.29 seconds</u>

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0
3 years ago
The diagram below shows the path of a planet around a star.
Anit [1.1K]

Answer:

Point C

Explanation:

Centripetal acceleration ac is inversely proportional to radius of orbit so it is greatest at point C.

7 0
3 years ago
Find the force exerted by each rope in the sign below
mixas84 [53]

Answer: Example 1: Consider a crate being pulled along a frictionless floor (while such a floor is very hard to find, this will still help us understand the concept and we can return to this situation later, after considering friction, and solve it more realistically).

Consider a crate being pulled along a horizontal, frictionless floor. A rope is tied around it and a man pulls on the rope with a force of T. T is the tension in the rope. What happens to the crate?

Before we can apply Newton's Second Law,

F = m a

we must find the net force -- the vector sum of all the forces -- acting on the object. In addition to the force T exerted by the rope, what other forces act on the object?

As discussed in class, in Mechanics, we can restrict our attention to "contact" forces and "gravity". That means gravity pulls down on this crate with a force equal to its weight, w. But the floor supports the crate. The floor responds by pushing up on the crate with a force we call the normal force. "Normal" means "perpendicular". We will call this force n; you may also encounter it labeled N or FN.

Explanation:

4 0
3 years ago
Calculate the net force on your 0.50-cm2 eardrum that air exerts on the inside and the outside after you drive from Denver, Colo
tekilochka [14]

Answer:

1.0563408 N

Explanation:

\rho = Density of air = 0.8 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Altitude

A = Area = 0.5 cm²

Pressure

p=\rho gh\\\Rightarrow p=0.8\times 9.81\times (4301-1609)\\\Rightarrow p=21126.816\ Pa

Pressure

p=\frac{F}{A}\\\Rightarrow F=pa\\\Rightarrow F=21126.816\times 0.5\times 10^{-4}\\\Rightarrow F=1.0563408\ N

The net force on your ear is 1.0563408 N

6 0
3 years ago
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