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Luba_88 [7]
4 years ago
10

A molecule has two atoms that are bonded to the central atom and one lone pair of electrons around this central atom. What is th

e shape of the molecule?
bent
linear
trigonal planar
trigonal pyramidal
Chemistry
2 answers:
alex41 [277]4 years ago
3 0
The shape of the molecule is trigonal planar.
For example, H₂O:
     ..
    O
  /    \
H     H

Sholpan [36]4 years ago
3 0

Answer:

bent

Explanation:

Let’s take the example of SO₂, here the central S atom has 6 valence electrons. S uses 1 pair of electron to form a double bond with each O atom. So, S in total uses four of its valence electrons to form two double bonds with two O atoms. Now after bond formation two electrons are still left on S, thus S has a lone pair of electron. In the absence of a lone pair of electron on S, SO₂ would have a linear structure, O=S=O. However, the lone pair-bond pair repulsion causes SO₂ to have a bent structure.

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An acid is used to bring the pH of a solution from pH 9 to pH 6. How many times more acidic is the final solution than the initi
Papessa [141]

Answer:

The final solution is 1.5 times more acidic than the initial solution

Explanation:

5 0
3 years ago
Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl
saw5 [17]

Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a)    HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)

Will be written as:

H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b)   Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)

Will be written as:

  Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}

Similarly here,  there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c)   NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)

Will be written as:

Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d)    Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g) is an oxidation-reduction reaction.

7 0
3 years ago
What typefs) of bonding would be expected for each of the following materials: solid xenon, calcium fluoride (CaF, bronze, cadmi
klio [65]

Answer:

a) Solid Xenon - only van der waals  forces of attractions.

b) Calcium Fluoride - Ionic Bonding

c) Bronze - Metallic Bonding

d) Cadmium telluride - Covalent bonding with slight ionic character.

e) Rubber - Covalent bonding with some van der Waals forces of attraction.

f) Tungsten - Metallic bonding

Explanation:

a) Xenon is  a noble gas having fully filled stable electronic configuration.

So, there is no bonding between xenon atoms in solid xenon.

Only van der waals forces of attraction are found.

b) Calcium fluoride is an ionic compound formed from calcium (2+) and Fluoride ion.

c) Bronze is an alloy formed mainly from copper and tin which are both metals.

So, metallic bonding is  in found in bronze.

d) Cadmium telluride is formed form cadimium (2+) ion and Telluride ion with -2 charge.

So, it has slight ionic character with predominant covalent bonding

e) Rubber is a polymer which is formed from isoprene units.

So, covalent bonding exists along with van der waals forces.

f) Tungsten is a metal. So, metallic bonding is found between the atoms of tungsten.

8 0
3 years ago
CO_2 sublimes readily at 25°C. Which properties are usually associated with a compound that undergoes this kind of change?
antoniya [11.8K]

Explanation:

Sublimation is defined as a process in which solid state of a substance directly changes into vapor or gaseous state without undergoing liquid phase.

For example, naphthalene balls show sublimation at room temperature.

As this process does not cause any change in chemical composition of a substance. Hence, it is known as a physical process.

Similarly, when CO_{2} sublimes readily at 25^{o}C. This shows change in physical state of carbon dioxide is taking place, i.e, from solid to gaseous phase.

Thus, we can conclude that when CO_{2} sublimes readily at 25^{o}C then it means physical properties are usually associated with a compound that undergoes this kind of change.

4 0
3 years ago
What is the element for I am a metal and I have 6 Neutrons. PLEASE ANSWER TO MY QUESTION QUICKLY!!!!
Papessa [141]

Answer:

carbon-12

Explanation:

carbon 6/12 isotope has 6 neutrones and it is considered as a metal.

7 0
3 years ago
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