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-Dominant- [34]
2 years ago
14

If the specific heat of water is 4. 18 j/g∙°c, how much heat is required to increase the temperature of 1. 20 kg of water from 2

3. 00 °c to 39. 00 °c?
Chemistry
1 answer:
Mkey [24]2 years ago
8 0

The heat required to increase the temperature of 1.20 g of water is  80,256 k/j

<h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

4. 18 J heat is required to change the temperature of 1.20 kg of water from 23. 00 °c to 39. 00 °c.

The heat required to raise temperature is the product of mass, specific heat and temperature change

1,200 × 4.18 × (39 − 23) = 80,256

Thus, the heat required to increase the temperature of 1.20 g of water is  80,256 k/j

Learn more about specific heat

brainly.com/question/11297584

#SPJ4

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Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

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\large \boxed{\text{-851.4 kJ/mol}}

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\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

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\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

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