Answer:
The ration of the molar solubility is 165068.49.
Explanation:
The solubility reaction of the magnesium hydroxide in the pure water is as follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)


Solubility of
in 0.180 M NaOH is a follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S+0.180M
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)



Therefore, The ration of the molar solubility is 165068.49.
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
Answer:
The answer to your question is U-234
Explanation:
Data
Thorium-234
beta emission twice
Definition
Beta emission is when a beta particle (electron) is emitted from an atomic nucleus.
First beta emission
²³⁴₉₀Th ⇒ ²³⁴₉₁Pa + e⁻
Second beta emission
²³⁴₉₁ Pa ⇒ ²³⁴₉₂U + e⁻
The atom will be Uranium-324
4.5 billion years old
Hope this helps!!!
Triplet multiplicity would expect in a 1h NMR spectrum for the indicated proton(s).
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