Question

Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-

Answer 1

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

• 113.4 g ÷ 46 g/mol = 2.465 mol

Then we use the PV=nRT formula, where:

• P = 1atm & T = 273K (This means STP)

• n = 2.465 mol

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• V = ?

Input the data:

• 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And solve for V:

• V = 55.18 L