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Step2247 [10]
3 years ago
6

Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-

Chemistry
1 answer:
Karolina [17]3 years ago
6 0

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

  • 113.4 g ÷ 46 g/mol = 2.465 mol

Then we<u> use the PV=nRT formula</u>, where:

  • P = 1atm & T = 273K (This means STP)
  • n = 2.465 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

Input the data:

  • 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And <u>solve for V</u>:

  • V = 55.18 L
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The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
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2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)
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