From Q = mcΔT, we can rearrange the equation to solve for mass, m = Q/cΔT. The specific heat capacity, c, of solid gold is 0.129 J/g °C. I'm assuming that the energy is given in joules, as it's not specified in the question as written.
m = Q/cΔT = (35.73 J)/(0.129 J/g °C)(40.85 °C - 0.85°C)
m = 6.92 g of gold was present
Answer:
The projection of the Fisher projection of D-Fructose and D-glucose is that The carbonyl carbon in D-glucose is carbon 1 (aldehyde), whereas in D-fructose, the carbonyl group is on carbon 2 (ketone).
Explanation:
An aldehyde is a compound containing a functional group with the structure −CHO, consisting of a carbonyl center and
A ketone is a functional group with the structure RC(=O)R', where R and R' can be a variety of carbon-containing substituents.
Answer:
9.1747x10⁻²⁵g
Explanation:
The mass defect is the difference between the mass of a nucleus and the mass of its particles. The nucleus is formed by protons and neutrons. The atomic number of Cobalt is 27, which means that it has 27 protons in its nucleus. The number of neutrons is the mass (60) less than the number of protons, so it is 33.
Then:
Mass of 27 protons = 27 x 1.00728 = 27.19656 amu
Mass of 33 neutrons = 33 x 1.00867 = 33.28611 amu
Total mass = 60.48267 amu
Mass defect = 60.48267 - 59.9338
Mass defect = 0.54887 amu
1 amu = 1.66054x10⁻²⁴ g, so 0.54887 amu = 9.1747x10⁻²⁵g
Answer:
%age Yield = 20.12 %
Solution:
The Balance Chemical Reaction is as follow,
Cl₂ + 3 F₂ → 2 ClF₃
According to Equation ,
114 g (3 mole) F₂ produces = 184.88 g (2 moles) of ClF₃
So,
19.2 g of F₂ will produce = X g of ClF₃
Solving for X,
X = (19.2 g × 184.88 g) ÷ 114 g
X = 31.13 g of ClF₃ (Theoretical Yield)
As we know,
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
%age Yield = (6.3 g ÷ 31.3 g) × 100
%age Yield = 20.12 %
