As water is boiled, kinetic energy causes<span> the </span>hydrogen bonds to break<span> completely and allows water molecules to escape into the air as gas (steam or water vapor). When water freezes, water molecules form a crystalline structure maintained by </span>hydrogen bonding<span>. Solid water, or </span>ice<span>, is less dense than liquid water.</span>
First we will calculate the number of moles of Iron:

, where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.

moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So

where 32 is the Atomical Weight of Oxygen (16 x 2).
=>

g
Answer:
- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.
- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.
- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.
Explanation:
Hello,
It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:
![pH=-log([H^+])\\](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%5C%5C)
![[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
![pOH=-log([OH^-])](https://tex.z-dn.net/?f=pOH%3D-log%28%5BOH%5E-%5D%29)
![[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-pOH%7D%3D10%5E%7B-7%7D%3D1x10%5E%7B-7%7DM)
Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.
Best regards.
This is true, vapor is just evaporated water. Like in machines, you have to fill it up with water so your machine can produce the water vapor. Hope this helps!!
This method of quantitative determination of percent purity is titrimetric reactions. These reactions most commonly involve neutralization reactions between an acid and a base. Then, we look at the neutralization reaction:
H₂C₂O₄ + 2 NaOH ⇒ Na₂C₂O₄ + 2 H₂O
So, we do the stoichiometric calculations. The important data we should know is the molar mass of oxalic acid which is equal to 90 g/mol.
(0.2283 mol/L NaOH * 0.3798 L * 1 mol H₂C₂O₄/ 2mol NaOH * 90 g/mol H₂C₂O₄) ÷ 0.7984 g *100%
= 488%
This is impossible. The purity can't be more than 100%. Looking at our calculations and the balance reaction, all steps were done correctly. So, I think there is some typographical error in the given. The mass of the sample should be 7.984 g. Then, the answer would be 48.87% purity.