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Elis [28]
3 years ago
10

15 POINTS!!!! (TWO QUESTIONS)

Chemistry
2 answers:
kumpel [21]3 years ago
8 0
Kinetic Energy is tearing a paper but sound you have it in their.


Mechanical energy for bike.
EleoNora [17]3 years ago
7 0
Tearing paper is sound energy.
Riding a bike is mechanical energy
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Given the following isotopes of strontium, calculate the average atomic mass.
vodka [1.7K]

Answer:

87.5198

Explanation:

(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98

8751.98 / 100 = 87.5198

3 0
3 years ago
What action is a result of gravity in relation to moving tectonics plates
yarga [219]

Answer:

When the denser tectonic plate dives beneath another plate it is due to the high energy by the Earth’s gravity that pushes into the mantle. Earth’s tides, which are caused by a gravitational tug of the Moon and the Sun, also put extra strain on geological faults. how to prepare for an earthquake

Explanation:

6 0
3 years ago
What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?
zaharov [31]

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

<h3>What is ionization energy?</h3>

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • E_n = \frac{E_0 × Z^{2}}{n^{2}}

where

E_0  \: is  \: ground  \: state  \: energy  \: of \:  hydrogen \:  atom \:  = -13.6 eV \\

  • Z = 1
  • n = 11

substituting the values:

E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \:  =  - 0.112 \: eV

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179

5 0
2 years ago
I need help pls Where does it belong to?​
Daniel [21]
The answer is B. Fungi,Protists
6 0
3 years ago
Ba(oh)2 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.750 m ba(oh)2 solution.
Sindrei [870]

The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is

[Ba2+] = 0.750 M

[OH-]= 1.50 M

<h3>calculation</h3>

write the equation for dissociation

that is  Ba(OH)2  (s)→ Ba2+(aq)  + 2OH-(aq)

by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M

by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of  OH- =0.750 M x2/1=1.50 M

7 0
4 years ago
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