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Elis [28]
3 years ago
10

15 POINTS!!!! (TWO QUESTIONS)

Chemistry
2 answers:
kumpel [21]3 years ago
8 0
Kinetic Energy is tearing a paper but sound you have it in their.


Mechanical energy for bike.
EleoNora [17]3 years ago
7 0
Tearing paper is sound energy.
Riding a bike is mechanical energy
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According to scientists across the globe, Pluto is not a "planet", but a "dwarf planet." This also is determined when you were born and taught different ideals, cause everyone changed their sort of learning on planets overtime in our generation. Hope this helped!

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Which part or parts of the paragraph indicate the relationship between public support and the enforcement of environmental polic
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Explanation:

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222 g of MTBE (CO(CH3)4) are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). Assume that the de
Eva8 [605]

Answer:

Explanation:

From the information given:

(a)

Concentration \ in \ mg/L = \dfrac{Mass \ of \ MTBE \ in \ mg}{Total \ volume (in \ L)}

Concentration \ in \ mg/L = \dfrac{222 \times 10^3 \ mg}{22}

Concentration \ in \ mg/L = 111 \times 10^3 \ mg/L

(b)

number \ of \ mole s= \dfrac{mass}{molar \ mass } \\ \\ number \ of \ mole s=\dfrac{222 \ g}{88.15 \ g/mol} \\ \\ \mathbf{= 2.518 mol}

(c)

w/w \ percentage = \dfrac{mass \ of \ MTBE }{mass \ of \ solution (RFG)}\times 100\%

where; \\ \\ mass \  of \  (RFG) = 2L \times 0.70 g/mL \\ \\ mass \  of \  (RFG) = 2000 ml \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 1400 g

∴

w/w \ percentage = \dfrac{222 \ g}{1400 \ g}\times 100\% = \mathbf{15.8\%}

(d)

Volume of MTBE =\dfrac{mass \ of \ MTBE}{density \ of \ MTBE}

Volume \ of \ MTBE = 300 \ mL\\

∴

v/v\% = \dfrac{volume \ of \ MTBE}{volume \ of \ RFG} \\ \\ v/v\% =\dfrac{300 \ mL}{2000 \ mL}\times 100\% \\ \\ \mathbf{v/v\% = 15.00\%}

(e)

From \the  \ given \  information; \\ \\ 2.5184 \ moles\ of  \ MTBE contain  \ 2.5184  \ mole of oxygen

∴

mass of oxygen MTBE = 2.5284 mol \times 16\ g/mol \\ \\ mass of oxygen MTBE = 40.3 9 \ g\\ \\ mass\ of \ RFG = 1400 g

∴

\% w/w = \dfrac{mass \ of \ oxygen}{mass \ of RFG }=\dfrac{40.22 \ g}{1400 \ g} \times 100\%

\% w/w == 2.88\%

3 0
3 years ago
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The formula for acetic acid is CH3COOH. Seana wants to know how many oxygen atoms are in 0.12 moles of acetic acid. O a. 1x 10^2
MA_775_DIABLO [31]

Answer:

c. 1.4 x 10²³ oxygen atoms

Explanation:

The number of oxygen atoms in one molecule of CH₃COOH is 2.

Avogadro's constant relates the number of molecules in one mole:

6.022 × 10²³ mol⁻¹

Thus, the number of oxygen atoms in one molecule of acetic acid can be converted to the number of oxygen atoms in one mole of acetic acid:

(2 oxygen atoms / molecule)(6.022 × 10²³ molecule / mol) = 1.204 x 10²⁴ atoms per mole

Finally, the number of oxygen atoms in 0.12 moles of acetic acid are calculated:

(1.204 x 10²⁴ atoms / mol)(0.12 mol) = 1.4 x 10²³ atoms/mol

6 0
3 years ago
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