Full Question;
What volume of a 0.150 M solution of KOH must be added to 450.0 mL of the acidic solution of 300ml of 0.450M HCL to completely neutralize all of the acid? Express the volume in liters to three significant figures.
Answer:
0.9l
Explanation:
First thing's first, we have to write out the balanced chemical equation.
KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)
Potassium hydroxide, KOH, and hydrochloric acid, HCl, react in a 1:1 mole ratio to produce aqueous potassium chloride, KCl, and water.
From the reaction;
Na = Nb
Where Na = Number of moles of acid
Na = Ca * Va = 0.450 * 0.300 = 0.135
Nb = Cb * Vb = Cb * 0.150
Na = Cb * 0.150
0.135 = Cb * 0.150
Cb = 0.135 / 0.150 = 0.9L
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Answer:
Dissociation Equations Worksheet
Write balanced chemical equations to represent the slight dissociation or the
complete dissociation for 1 mole of the following compounds. In the case of slight
dissociation use a double arrow and for complete dissociation use a single arrow.
Include phase notation in the equations.
1) silver chloride
2) sodium acetate
3) ammonium sulfate
4) calcium carbonate
5) potassium carbonate
6) sodium hydroxide
7) silver chlorate
8) iron(II) sulfate
9) lead(II) phosphate
10) lead(II) chromate
11) iron(III) chloride
12) calcium nitrate
13) iron(III) oxide
14) copper(II) sulfate
15) mercury(II) sulfide
16) zinc chloride
17) lead(II) acetate
18) aluminum phosphate
Solutions
1) AgCl(s) ↔ Ag+
(aq) + Cl-
(aq)
2) NaC2H3O2(s) Æ Na+
(aq) + C2H3O2
-
(aq)
3) (NH4)2SO4(s) Æ 2NH4
+
(aq) + SO4
2-(aq)
4) CaCO3(s) ↔ Ca2+(aq) + CO3
2-(aq)
5) K2CO3(s) Æ 2K+
(aq) + CO3
2-(aq)
6) NaOH(s) Æ Na+
(aq) + OH-
(aq)
7) AgClO3(s) Æ Ag+
(aq) + ClO3
-
(aq)
8) FeSO4(s) Æ Fe2+(aq) + SO4
2-(aq)
9) Pb3(PO4)2(s) ↔ 3Pb2+(aq) + 2PO4
3-(aq)
10) PbCrO4(s) ↔ Pb2+(aq) + CrO4
2-(aq)
11) FeCl3(s) Æ Fe3+(aq) + 3Cl-
(aq)
12) Ca(NO3)2(s) Æ Ca2+(aq) + 2NO3
-
(aq)
13) Fe2O3(s) ↔ 2Fe3+(aq) + 3O2-(aq)
14) CuSO4(s) Æ Cu2+(aq) + SO4
2-(aq)
15) HgS(s) ↔ Hg2+(aq) + S2-(aq)
16) ZnCl2(s) Æ Zn2+(aq) + 2Cl-
(aq)
17) Pb(C2H3O2)2(s) Æ Pb2+(aq) + C2H3O2
-
(aq)
18) AlPO4(s) ↔ Al3+(aq) + PO4
3-(aq)
Explanation:
Iron becomes rusted especially in damp air but never in a dry air, this is one of the many unique characteristics of iron. Iron is also ductile and malleable. It is found in the seventh group of the periodic table. It has four different and unique crystalline forms and completely dissolves in dilute acids. The two chemical compounds that can be found or made from iron are the bivalent iron also known as ferrous and the trivalent iron or known as ferric compounds.
Answer:
Your answer is potASSium Iodide
Explanation:
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