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koban [17]
3 years ago
11

Balanced complete ionic and net ionic equations

Chemistry
2 answers:
Citrus2011 [14]3 years ago
6 0
1) The balanced chemical equation will be : 
<span>    2HClO4 (aq) + Ca(OH)2(aq) → Ca(ClO4)2 (aq) + 2H2O (l) 
</span>
 Ionic equation: 
<span> 2H+(aq) + 2ClO4-(aq) +Ca2+(aq) + 2OH-(aq) → Ca2+(aq) + 2ClO4-(aq)  +2H2O(l) 
</span>
<span> Net ionic equation: </span>
<span> 2H+ (aq) + 2OH-(aq) → 2H2O(l) 
</span>
 2) <span>Molecular equation: </span>
<span> H2SO4(aq) + Li2SO3(aq) → Li2SO4(aq) + SO2(g) + H2O(l) </span>
<span>
 Ionic equation: </span>
<span> 2H+ (aq) + SO4 2-(aq) + 2Li+ (aq) + SO3 2-(aq) → 2Li+(aq) + SO4 2-(aq) +  SO2(g) + H2O(l) 
</span>
<span> Net ionic equation: </span>
<span> 2H+(aq) + SO3 2-(aq) → SO2(g) + H2O(l)</span>
Vladimir79 [104]3 years ago
4 0

Answer :

(1) The net ionic equation will be,

H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

(2) The net ionic equation will be,

2H^+(aq)+SO_3^{2-}(aq)\rightarrow H_2O(l)+SO_2(g)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(1) The balanced ionic equation will be,

HClO_4(aq)+Ca(OH)_2(aq)\rightarrow Ca(ClO_4)_2(aq)+2H_2O(l)

The ionic equation in separated aqueous solution will be,

H^+(aq)+ClO_4^-(aq)+Ca^{2+}(aq)+2OH^-(aq)\rightarrow Ca^{2+}(aq)+2ClO_4^-(aq)+2H_2O(l)

In this equation, Ca^{2+}\text{ and }ClO_4^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)

(2) The balanced ionic equation will be,

H_2SO_4(aq)+Li_2SO_3(aq)\rightarrow Li_2SO_4(aq)+H_2O(l)+SO_2(g)

The ionic equation in separated aqueous solution will be,

2H^+(aq)+SO_4^{2-}(aq)+2Li^+(aq)+SO_3^{2-}(aq)\rightarrow 2Li^+(aq)+SO_4^{2-}(aq)+H_2O(l)+SO_2(g)

In this equation, Li^+\text{ and }SO_4^{2-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2H^+(aq)+SO_3^{2-}(aq)\rightarrow H_2O(l)+SO_2(g)

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