First find the slope of f(x).
m=(y2-y1)/(x2-x1)
m=(1-5)/(2-0)
m=-4/2
m=-2
y=-2x+b, using (2,1) we can solve for the y-intercept, "b"
1=-2(2)+b
1=-4+b
5=b
y=-2x+5
So f(x) has a y-intercept of 5
g(x)=6m+3
So g(x) has a y-intercept of 3
h(x)=3x+4
So h(x) has a y-intercept of 4
Then g(x) has the lowest y-intercept of just 3.
Answer:
My answer is 20ft I'm not really sure but hope this helps
Answer:
We conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.
Step-by-step explanation:
Given the expression
y = 2x² + 3x
Substituting x = 0
y = 2(0)² + 3(0)
y = 0+0
y = 0
Thus, the ordered pair is: (0, 0)
Now, substituting x = -2
y = 2x² + 3x
y = 2(-2)² + 3(-2)
y = 8 - 6
y = 2
Thus, the ordered pair is: (-2, 2)
Therefore, we conclude that the two ordered pairs (0, 0) and (-2, 2) are the solutions of the equation y = 2x² + 3x.
Answer:
1.2 I think sorry if I'm wrong double check to see
Step-by-step explanation:
This is what I thought of oof so sorry if it incorrect
