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ElenaW [278]
3 years ago
6

All of the following metals replace hydrogen of an acid except.........

Chemistry
1 answer:
trapecia [35]3 years ago
8 0

Answer:

Au

Explanation:

Below hydrogen on reactivity table.

hydrogen would rather give up its electrons.

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Gnesinka [82]
276 grams of carbon in 23.0 moles
3 0
3 years ago
Which of the following examples best demonstrates kinetic energy?
Vlada [557]
Answer:-

Thanks for not describing your question well enough
4 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
3 years ago
According to the following position vs. Time graph the bicyclist was
julia-pushkina [17]

Answer:

According to the following position vs. Time graph the bicyclist was : D

D. Not moving for the first two seconds, then begin moving at the constant speed.​

Explanation:

Speed = \frac{Distance}{time}

Along Y-axis = Distance in meters

Along X-axis = Time taken in second

  • For first 2 seconds the The object has not changed its position.There is Zero distance covered.So , Speed = 0
  • After 2 second,The Object changed the distance by equal amount in equal interval of time.(Uniform Speed).Hence at each point after 2 second, there is same value speed
3 0
3 years ago
Why doesnt ammonia support combustion?
earnstyle [38]
We need the reading for this I think
4 0
3 years ago
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