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Sergio [31]
2 years ago
7

Explain why two obtuse angles cannot be supplementary to another.

Mathematics
2 answers:
igor_vitrenko [27]2 years ago
6 0
A obtuse have to be 180 but 2 obtuses is impossible 
Nuetrik [128]2 years ago
5 0
It's impossible. Supplements need to add up to 180 degrees, and in order to be obtuse, the angles would both need to be larger than 90 degrees.
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Three consecutive even numbers add up to 36. Select all of the following equations that will find the lowest number of the three
Misha Larkins [42]

Equation A find the lowest number of the three. Equation A satisfies the given conditions.

<h3>What is even number? </h3>

If the number is divisible by 2 then the number will be an even number. Similarly, the number is not divisible by 2 then the number will be an odd number.

Assume the three consecutive integers are 2x,2x+2,2x+4

The sum of the three consecutive even numbers are 36;

x+x+2+x+4 = 36

3x+6=36

3x=30

x=10

The three integers are found as;

x =10

x+2 = 10+2 = 12

2x+4 =10+4=14

Hence, equation A find the lowest number of the three. Equation A satisfies the given conditions.

To learn more about the even number, refer to the link;

brainly.com/question/2289438

#SPJ1

5 0
2 years ago
The school orchestra has 20 woodwinds, 20 brass instruments, 45 percussionists and 15 strings. Select the portion of the instrum
Alona [7]

Find total instruments:

20+20+45+15 = 100

20 are brass

The portion would be number of brass over total:

20/100 which reduces to 1/5 are brass

6 0
3 years ago
Read 2 more answers
Combine the like terms to create an equivalent expression:<br> \large{-12-6p-(-2)}−12−6p−(−2)
Harlamova29_29 [7]

Answer:

-12p-20

Step-by-step explanation:

{-12-6p-(-2)}−12−6p−(−2)

-12-6p+2−12−6p+2

-12p-20

4 0
2 years ago
What’s the answer pleaseeeeeeeee
slega [8]

y^2 +6^2 = 12^2

y^2 +36 = 144

y^2 = 108

sqrt(108) = 10.392 = 6sqrt(3)

 Answer is B 6sqrt(3)

7 0
3 years ago
Find the area of the shaded region.
taurus [48]

Answer:

426.96 \:  {km}^{2}

Step-by-step explanation:

Area of the shaded region = Area of triangle with base 40 km and height 27 km - Area of circle with radius (12/2) 6 km.

=  \frac{1}{2}  \times 40 \times 27  - 3.14 \times  {(6)}^{2}  \\  \\  = 20 \times 27 - 3.14 \times 36 \\  \\  = 540 - 113.04 \\ \\   = 426.96 \:  {km}^{2}

5 0
3 years ago
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