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2 years ago

Explain why two obtuse angles cannot be supplementary to another.

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

6 0

A obtuse have to be 180 but 2 obtuses is impossible

Nuetrik [128]2 years ago

5 0

It's impossible. Supplements need to add up to 180 degrees, and in order to be obtuse, the angles would both need to be larger than 90 degrees.

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To cover a rectangle region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. W

gulaghasi [49]

We know that the perimeter of a rectangle is 2(width)+2(length). We can multiply the length by 2 to find out how much remaining fencing we have, then divide that number by 2 to find the width.

15.5*2=31
170.5-31=139.5
139.5/2=69.75

A possible width is 69.75 feet.

4 0

2 years ago

Flying against the wind, a jet travels 4400mi in 8 hours. Flying with the wind, the same jet travels 5820mi in 6 hours. What is

Viefleur [7K]

Let J = rate of jet in still airLet W = rate of wind Distance formula: d = rt / r = d/t Flying against the wind the jet flies at a rate of J - W = 1860 miles/3 hours = 620 miles per hourFlying with the wind the jet flies at a rate of J+W = 9180 miles/9 hours = 1020 miles per hour The average of these 2 rate is the speed of the jet in still air J = (620+1020)/2 = 820 miles per hour J - W = 620

820 - W = 620
W = 820 - 620 = 200 miles per hour The jet in still air flies at a rate of 820 mph(miles per hour)The wind speed is 200 mph(miles per hour)

3 0

3 years ago

Someone please help with these and explain your answer for both!!! I will give brainliest if correct!!!

goldenfox [79]

Answer:

Step-by-step explanation:

We have congruent angles in the middle and 2 sides are congruent as well which makes (Angle-Side-Side) which doesn't work for congruent triangles.

3 0

2 years ago

Read 2 more answers

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0

3 years ago

a printing press will print 6,000 copies in 20 minutes. A second press can print 15000 copies in 60 minutes. How many more copy

Usimov [2.4K]

Printing Press 1: 6000/20 minutes which is 300/minute
Printing Press 2: 15000/60 minutes which is 250/minute

The faster press (the first one) would print 50 more copies per minute than the slower one (the second one).

7 0

2 years ago