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3 years ago

What is the formula for equity

Mathematics

1 answer:

-BARSIC- [3]3 years ago

3 0

Assets minus Liabilities

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Simplify:<br> (2x - 3)(3x + 4)

UNO [17]

(2x - 3) (3x + 4) = 6x² + 8x - 9x - 12 = <u>6x² - x - 12 </u>

5 0

3 years ago

4. Simplify the following using the quotient rule of exponents:

7nadin3 [17]

Answer:

31=1/1

33=1/1

30=3/10

3-=-3

Step-by-step explanation:

7 0

3 years ago

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

5 0

3 years ago

If each quadrilateral below is a square, find the missing measures<br><br>solve for X

Studentka2010 [4]

Answer:

i think x = 18.5

Step-by-step explanation:

6x-21 = 90°

6x = 90+21

6x = 111

x = 111/6

x = 18.5

3 0

2 years ago

-5x-6(-6+3x)=105 what is the answer

lyudmila [28]

Answer:

x = -3

Step-by-step explanation:

expand -23x + 36 = 105

subtract 36 from both sides -23x +36 -36 = 105 - 36

Simplify -23x = 69

Divid both sides by -23: -23x / - 23 = 69 / -23

x = -3

3 0

4 years ago