Length = 8 cm Derimeter = 22 cm Breadth = ?

Inga [223]

Answer:

A.v=п*1/4*S^3

Step-by-step explanation:

the formula for the volume of a cylinder is v=п*r^2*h. here r=d/2=S/2 so r^2=S^2/4. h is the same lenght as the side of the cube so h=s. and then you just have to substitute r and s in the formula

4 0

3 years ago

Read 2 more answers

Help me please. thank you!! <3

Veseljchak [2.6K]

We will find the missing side or Hypotenuse using the pythogoras theorem...

The theorem states that the Square of hypotenuse is equal to the sum of the square of the base and square of perpendicular.

 $\sf\:H^{2}=P^{2}+B^{2}$ 

P = 5
B = 10

$\sf\:H^{2}= {5}^{2} + {10}^{2}$

$\sf\:H^{2}=25 + 100$

$\sf\:H^{2}=125$

$\sf\:H = \sqrt{125}$

$\sf\:H = 5 \sqrt{5}$

7 0

2 years ago

Please Please please

Nadusha1986 [10]

Answer:

is the name of your account from little mermaid? :DDD

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

now just refer to the above ( also copy and paste the above on your computer some where so you have it always)

sin( D )= 28 / 53

sin( E ) = 45 / 53

cos(D) = 45 / 53

cos(E) = 28 / 53

4 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

If f(x) = x^2 - 4x + 1, find the range of f(x). {y: y ≥ -3} {y: y ≥ 13} all reals

Tomtit [17]

Hello :
y= x² - 4x + 1
calculate : x
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if y+3 ≥ 0
y ≥ -3
the range is : {y: y ≥ -3}

8 0

3 years ago

Length = 8 cmDerimeter = 22 cmBreadth = ?​

Length = 8 cmDerimeter = 22 cmBreadth = ?