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Alex17521 [72]
3 years ago
10

Lewis structure for CH3(CH2)CH(CH3)2

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

Explanation:That’s right

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NH3 is a weak alkali that does not dissociate fully into its solution. Which of the following is true about NH3?
NemiM [27]

Answer:

Answer:

B. It's dissociation is a reversible reaction

Explanation:

NH3 is a weak alkali that does not dissociate fully into its solution. Only parts of the ammonia takes part in the dissociation process.

NH3 + H20 —> NH4+ + OH-

This dissociation is reversible which means the reactants can be formed from the product gotten from the dissociation

It has a high pH due to its basic nature. It also has a Low concentration of H+ ions and not all the OH- ions are released.

6 0
3 years ago
Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
Zanzabum

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

4 0
3 years ago
How many molecules of carbon dioxide are present in 4.81042 mol of that substance?
Korvikt [17]

1 mol is equal to 6.02×10∧23 molecules.

first put in the calculator 4.81042 × 6.02 then hit EXP or 2nd then EE. (Depends on the type of calculator). then put in 23 and press equal.

The calculator will says 2.89587284×10∧24.

So the answer will be 2.90×10∧24.

I mot sure if the 2.90 is correct but it is close to the answer. it really depends how you want to round it. As long as the decimals are close the answer doesn't matter. Hope this helps. Please mark as Brainliest.

4 0
4 years ago
2. HBIO3 name this acid.​
aleksandr82 [10.1K]

Answer:

Hydroxy(oxo)bismuthine oxide

3 0
3 years ago
How many moles would be equal to 22.4 g of CO2?
Rzqust [24]

Answer:

Number of moles = 0.51 mol

Explanation:

Given data:

Mass of CO₂ = 22.4 g

Number of moles = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Molar mass of CO₂ = 44 g/mol

by putting values,

Number of moles = 22.4 g/ 44 g/mol

Number of moles = 0.51 mol

4 0
3 years ago
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