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lukranit [14]
3 years ago
14

In the laboratory, a student adds 50.4 mL of water to 16.5 mL of a 0.880 M hydroiodic acid solution. What is the concentration o

f the diluted solution? Assume the volumes are additive. Concentration = M
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

Explanation:

idk

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an unknown molecule is found to consist of 24.2% carbon by mass, 4.0% hydrogen by mass and the remaining mass is due to chlorine
Paha777 [63]

Answer:

C3 H6 Cl 3

Explanation:

C -24.2%

H -  4.0%

Cl - (100-24.2 - 4.0)=73.8 %

We can take 100g of the substance, then we have

C -24.2 g

H -  4.0 g

Cl - 73.8 g

Find the moles of these elements

C -24.2 g/12.0 g/mol =2.0 mol

H -  4.0 g/1.0 g/mol = 4. 0 mol

Cl - 73.8 g/ 35.5 g/mol = 2.1 mol

Ratio of these elements gives simplest formula of the substance

C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1

CH2Cl

Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol

Real molar mass = 150  g/mol

real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3

So, Real formula should be C3 H6 Cl 3.

4 0
4 years ago
Read 2 more answers
Which technology was essential for the development of the cell theory?​
vodka [1.7K]

Answer: Microscope

Explanation: This is a kid answering :)

8 0
3 years ago
Which of the following is a necessary product of a combustion reaction?
BlackZzzverrR [31]

Answer:

Heat

Explanation:

explosions always make heat

8 0
3 years ago
How would your experimental formula of magnesium chloride “MgClx” have been affected if
aksik [14]
The compound is used in medicine as a source of magnesium ions, which are essential for many cellular activities. Magnesium chloride has also been used as a cathartic and in alloys. To low
6 0
4 years ago
A. 1720 kJ<br> B. 125.6 kJ<br> C. 3440 kJ<br> D. 4730 kJ
Feliz [49]

Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

Latent heat of vaporization = 1720 Kj/Kg

Energy required to vaporize 2kg gold = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  1720 Kj/Kg

Q = 3440Kj

7 0
3 years ago
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