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Ugo [173]
3 years ago
5

Chase is campaigning for class president and plans to distribute some campaign materials: 8 flyers and 12 buttons. He wants each

classroom to receive an identical set of campaign materials, without having any materials left over. What is the greatest number of classrooms Chase can distribute materials to?
Mathematics
1 answer:
rjkz [21]3 years ago
6 0
Answer: 4 classrooms

Explanation:
The greatest common factor of 8 and 12 is 4, so the answer would be 4 because Chase doesn’t want any leftover supplies.
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2 years ago
Is this a Percent Increase or Decrease Problem?
nydimaria [60]

Answer:

Percent Decrease

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3 0
2 years ago
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lara [203]
Answers with Explanation.


i. If we raise a number to an exponent of 1, we get the same number.

{10}^{1}  = 10

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

{10}^{2}  = 10 \times 10 = 100

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.



{10}^{3}  = 10 \times  {10}^{2}  = 10 \times 100 = 1000

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.


{10}^{4}  =  10 \times {10}^{3} = 10 \times 1000 =  10000

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.



{10}^{5}  = 10 \times  {10}^{4}  = 10 \times 10000 = 100000

{10}^{5}  = 100000

vi. Recall that,

{a}^{ - m}  =  \frac{1}{ {a}^{m} }
We apply this law of exponents to obtain,

{10}^{ - 2}  =  \frac{1}{{10}^{2} }  =  \frac{1}{100}

vii. We apply
{a}^{ - m}  =  \frac{1}{ {a}^{m} }
again to obtain,


{10}^{ - 3}  =  \frac{1}{ {10}^{3} }  =  \frac{1}{1000}





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3 years ago
F(x)=3x-1 g(x) x^3 -5x^2 <br> Find (f o g)(x)
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plz plz mark brainliest

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3 years ago
Read 2 more answers
Help quickly please!
stepladder [879]

Im not too sure, but C might work as an answer...

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3 years ago
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