Answer:
4 students needed
Step-by-step explanation:
We can divide 5/6 and then round it to the nearest tenth which is 0.8.
This means every 0.8 hours 1 student is completed with their work.
We can then divide 3 hours with the 0.8 hours to get 3.75 students additionally needed to cut the time to 3 hours.
Obviously, we can't have 3/4's of a student so we convert that into 1 student, ending up with 4 students additionally needed to complete the work in 3 hours.
Mathematical work:
5 students/6 hours
= 0.8 hours
0.8 hour/3 hours
=3.75 students
Round 3.75 to 4
4 students additionally needed.
Hope this helped.
Answer:
x
Step-by-step explanation:
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5.46 ÷ 3 = 1.82
1.82 x 5 = 9.1
The answer is "9.10"
<h3>Given</h3>
P = 3r + 2s
<h3>Find</h3>
the corresponding equation for s
<h3>Solution</h3>
First of all, look at how this is evaluated in terms of what happens to a value for s.
- s is multiplied by 2
- 3r is added to that product
To solve for s, you undo these operations in reverse order. The "undo" for addition is adding the opposite. The "undo" for multiplication is division (or multiplication by the reciprocal).
... P = 3r + 2s . . . . . . starting equation
... P - 3r = 2s . . . . . . -3r is added to both sides to undo addition of 3r
... (P -3r)/2 = s . . . . . both sides are divided by 2 to undo the multiplication
Note that the division is of everything on both sides of the equation. That is why we need to add parentheses around the expression that was on the left—so the whole thing gets divided by 2.
Your solution is ...
... s = (P - 3r)/2
Answer:
option B
Given : |x + 4| < 5
A. –5 > x + 4 < 5
B. –5 < x + 4 < 5
C. x + 4 < 5 and x + 4 < –5
D. x + 4 < 5 or x + 4 < –5
In general , |x|< n where n is positive
Then we translate to -n < x < n
|x + 4| < 5
5 is positive, so we translate the given absolute inequality to
-5 < x+4 < 5
So option B is correct