Answer:
m' = 4948.38 kg/s
Explanation:
For a case of 100% efficiency, the power produced must be equal to the rate of potential energy conversion
GIVEN THAT
Power = 100 MW
rate of Potential energy = (m')*g*h
100*10^6 = (m')*9.81*206
m' = 4948.38 kg/s
Answer:
ik the answer but I'm busy rn
Answer:
symbolic machine code.
Explanation:
The instructions in the language are closely linked to the machine's architecture.
