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aleksandrvk [35]
3 years ago
14

Based on the following passage, why might the government use the U.S. Army Corps of Engineers to undertake hydroelectric power p

rojects instead of allowing private businesses to undertake them?
Before World War I, most power projects were developed by private interests. During the Great Depression, president Franklin Roosevelt developed federal hydropower projects to give low-cost energy to consumers. The U.S. Army Corps of Engineers undertook three major hydroelectric power projects during this era: the Bonneville Dam on the Columbia River, the Fort Peck Dam on the Missouri River, and the Passamaquoddy Tidal Power Project in Maine. Congress organized the Bonneville Power Administration in 1937 to distribute the power and set usage rates for all power generated at Bonneville Dam.


Hydroelectric power is closely linked to national security.

Private businesses are by law disallowed from engaging in hydroelectric power projects.

The government would have less power to control the cost of electricity from privately funded projects.

Private businesses have less expertise in hydroelectric power than the U.S. Army Corps of Engineers.
Engineering
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

The government would have less power to control the cost of electricity from privately funded projects.

Explanation:

According to the given excerpt, the government, the government decided to take over most of the hydroelectric power projects as opposed to privately owned corporations which previously held a monopoly. The major reason was to provide low-cost energy to consumers.

This decision taken by the government to use the Army Corps of Engineers to undertake hydroelectric power projects instead of allowing private businesses to undertake them was to allow the government have more power to control the cost of electricity.

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A horizontal 2-m-diameter conduit is half filled with a liquid (SG=1.6 ) and is capped at both ends with plane vertical surfaces
luda_lava [24]

Answer:

Resultant force = 639 kN and it acts at 0.99m from the bottom of the conduit

Explanation:

The pressure is given as 200 KPa and the specific gravity of the liquid is 1.6.

The resultant force acting on the vertical plate, Ft, is equivalent to the sum of the resultant force as a result of pressurized air and resultant force due to oil, which will be taken as F1 and F2 respectively.

Therefore,

Ft = F1 + F2

According to Pascal's law which states that a change in pressure at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere, the air pressure will act on the whole cap surface.

To get F1,

F1 = p x A

= p x (πr²)

Substituting values,

F1 = 200 x π x 1²

F1 = 628.32 kN

This resultant force acts at the center of the plate.

To get F2,

F2 = Π x hc x A

F2 = Π x (4r/3π) x (πr²/2)

Π - weight density of oil,

A - area on which oil pressure is acting,

hc - the distance between the axis of the conduit and the centroid of the semicircular area

Π = Specific gravity x 9.81 x 1000

Therefore

F2 = 1.6 x 9.81 x 1000 x (4(1)/3π) x (π(1)²/2)

F2 = 10.464 kN

Ft = F1 + F2

Ft = 628.32 + 10.464

Ft = 638.784 kN

The resultant force on the surface is 639 kN

Taking moments of the forces F1 and F2 about the centre,

Mo = Ft x y

Ft x y = (F1 x r) + F2(1 - 4r/3π)

Making y the subject,

y = (628.32 + 10.464(1 - 4/3π)/ 638.784

y = 0.993m

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A closed system consisting of 4 lb of a gas undergoes a process during which the relation between pressure and volume is pVn 5 c
gayaneshka [121]

Answer:

V1=5<u>ft3</u>

<u>V2=2ft3</u>

n=1.377

Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

V=mv

state 1

V1=m.v1

V1=4lb*1.25ft3/lb=5<u>ft3</u>

state 2

V2=m.v2

V2=4lb*0.5ft3/lb=  <u> 2ft3</u>

PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

P1V1^n=P2V2^n

P1/P2=(V2/V1)^n

ln(P1/P2)=n . ln (V2/V1)

n=ln(P1/P2)/ ln (V2/V1)

n=ln(15/53)/ ln (2/5)

n=1.377

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3 years ago
(25%) A well-insulated compressor operating at steady state takes in air at 70 oF and 15 psi, with a volumetric flow rate of 500
lubasha [3.4K]

Answer:

You can look it up

Explanation: if you don't know what it is look it up on .

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A converging-diverging nozzle has an area ratio of 5.9. (1) Determine the (P0/Pt) values corresponding to the 1st, 2nd, and 3rd
nata0808 [166]

Answer:

Check the explanation

Explanation:

The Total pressure is the overall of fixed or static pressure p, the dynamic pressure q, as well as gravitational head. Total pressure can also be referred to as the measure of the overall energy of the airstream, and is the same to static pressure plus velocity pressure.

kindly check the step by step solution in the attached image below to Determine the (P0/Pt) values corresponding to the 1st, 2nd, and 3rd critical points.

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