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Kaylis [27]
3 years ago
14

A rectangular beam of width b = 15 in., effective depth d = 20.5 in., and total depth h = 23 in. spans 18.5 ft. between simple s

upports. It will carry a computed dead load of 1.08 kips/ft. including self-weight, plus a service live load of 2.29 kips/ft. Reinforcement consists of four evenly spaced No. 7 bars in one row. The clear cover on the sides is 2 in. Material strengths are fy = 60,000 psi and fc = 4000 psi. Compute the stress in the steel at full service load, and estimate the maximum crack width using (a) Equation 1 (see Slide No. 10) and (b) equation provided by the ACI Code (see Slide No. 11). Does the section meet the crack control requirement?

Engineering
1 answer:
jasenka [17]3 years ago
7 0

Attached is the solution to the question spelt out above.

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Given V1 = 8 vpp, R1 = 6 kΩ, V2 = 5 vpp, R2 = 3 kΩ, V3 = 10 vpp, R3 = 3 kΩ, and Rf = 14 kΩ, find Vout. Vout = vpp. (Round your a
iragen [17]

Answer:

Vout= 93.3V

Explanation:

For this question, consider circuit in the attachment 1.

This is the circuit of an inverting amplifier. In an inverting amplifier

Vout/Vin= -Rf/Rin

To calculate the Vout, we must find Rin and Vin. For this we must solve the input circuit (attachment 2)  using  Thevinine theorem. Thevnine theorem states that all voltage sources in a circuit can be replaced by an equivalent voltage source Veq and and all resistances can be replaced by an equivalent resistance Req. To find out Req all voltage sources must be short circuited (attachment 3)

1/Req= 1/R1+1/R2+1/R3

1/Req=1/6+1/3+1/3

Req=6/5

To find out Veq consider circuit in attachment 4. We will solve this circuit using nodal analysis. In nodal analysis, we use the concept that sum of currents entering a node is equal to the sum of currents leaving a node. So,

I1= I2+I3

(10-Veq)/6= (Veq-5)/3+(Veq-10)/3

Veq=8V

Now the input circuit can be simplified as shown in attachment 5. Solve for Vout using equation

Vout/Veq= -Rf/Req

Vout/8= -14/(6/5)

Vout= - 93.3

It is at an angle of 180° from Veq

7 0
3 years ago
What type of fire extinguisher is used for electrical fires.
AysviL [449]
The all purpose one will work or you could use type C I believe.
8 0
3 years ago
Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Viktor [21]

Answer:

Enthalpy, hsteam = 2663.7 kJ/kg

Volume, Vsteam = 0.3598613 m^3 / kg

Density = 2.67 kg/ m^3

Explanation:

Mass of steam, m = 1 kg

Pressure of the steam, P = 0.5 MN/m^2

Dryness fraction, x = 0.96

At P = 0.5 MPa:

Tsat = 151.831°C

Vf = 0.00109255 m^3 / kg

Vg = 0.37481 m^3 / kg

hf = 640.09 kJ/kg

hg = 2748.1 kJ/kg

hfg = 2108 kJ/kg

The enthalpy can be given by the formula:

hsteam = hf + x * hfg

hsteam = 640.09 + ( 0.96 * 2108)

hsteam = 2663.7 kJ/kg

The volume of the steam can be given as:

Vsteam = Vf + x(Vg - Vf)

Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)

Vsteam = 0.3598613 m^3 / kg

From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3

5 0
3 years ago
In a website browser address bar, what does “www” stand for?
Ludmilka [50]

Answer:

www stands for world wide web

Explanation:

It will really help you thank you.

3 0
3 years ago
Diodes can be used to protect electronic components from certain flowing in another Direction describe another application outsi
Anvisha [2.4K]

Answer:

Plumbing  using a one-way check valve to stop water flowing back on a pump when the pump shuts off.

Explanation:

Diodes are like check valves, keeping current from flowing both ways.  Used to create d.c. out of a.c by rectification.  Also to block flow if d.c. power like a battery is hooked up in reverse polarity.

4 0
3 years ago
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