HCl(aq) + KOH(aq) → H 2O(ℓ) + KCl(aq)
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The answer for the following problem is mentioned below.
Explanation:
Given:
mass of iron (m) = 15.75 grams
heat (q) = 1097 J
initial temperature () = 25°C
final temperature () = 177°C
To find:
specific heat (c)
We know;
c = q ÷ mΔT
where;
c represents the specific heat
q represents the heat
m represents the mass
t represents the temperature
c =
c = 0.45 J/kg°C
<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>
Hello!
The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):
So, the Heat absorbed by water is 1297,04 J
Have a nice day!
The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):
So, the Heat absorbed by water is 1297,04 J
Have a nice day!